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Levart [38]
3 years ago
12

The totals of the rows and columns of a two-way table are called borderline distributions.

Mathematics
2 answers:
Rudik [331]3 years ago
7 0
B.) False is the answer
Paraphin [41]3 years ago
7 0

Answer:

False

Step-by-step explanation:

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80 members decreased by 40%
aleksklad [387]
The answer would be 48 because....
 
First, you would multiply 80 and .40 (changed the percentage to decimal) which is 32

Then, subtract 80 and 32 to get 48
6 0
3 years ago
Due to a manufacturing error, 2 cans of regular soda were accidentally filled with diet soda and placed into a24 -pack.
Gennadij [26K]

Answer:

a) 1/48 or 2.0833%

b) 46/48 or 95.8333%

no it would not be unusual

c) I'm not sure sorry

5 0
3 years ago
Which trinomial is the product of the expression below?<br> (2r-5)(r+10
kkurt [141]
2r²+15r-50

hope this helps

8 0
3 years ago
A recent study focused on the number of times men and women send a WeChat message in a day. The information is summarized next.
Ratling [72]

Answer:

1)Null hypothesis:\mu_{men}=\mu_{women}

Alternative hypothesis:\mu_{men} \neq \mu_{women}

2) Two critical values are z_{\alpha/2}=-2.58 and z_{1-\alpha/2}=2.58

3) z=-2.40  

4) p_v =2*P(z

5) Comparing the p value with the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the mean number of times men and women send a Twitter message in a day.

Step-by-step explanation:

Data given and notation

\bar X_{men}=23 represent the mean for the sample men

\bar X_{women}=28 represent the mean for the sample women

\sigma_{men}=5 represent the population standard deviation for the sample men

\sigma_{women}=10 represent the population standard deviation for the sample women

n_{men}=25 sample size for the group men

n_{women}=30 sample size for the group women

t would represent the statistic (variable of interest)

\alpha=0.01 significance level provided

1)Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different, the system of hypothesis would be:

Null hypothesis:\mu_{men}=\mu_{women}

Alternative hypothesis:\mu_{men} \neq \mu_{women}

Since we know the population deviations for each group, for this case is better apply a z test to compare means, and the statistic is given by:

z=\frac{\bar X_{men}-\bar X_{women}}{\sqrt{\frac{\sigma^2_{men}}{n_{men}}+\frac{\sigma^2_{women}}{n_{women}}}} (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

2)Determine the critical value(s).

Based on the significance level\alpha=0.01 and \alpha/2=0.005 we can find the critical values with the normal standard distribution, we are looking for values that accumulates 0.005 of the area on each tail on the normal distribution.

For this case the two values are z_{\alpha/2}=-2.58 and z_{1-\alpha/2}=2.58

3) Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

z=\frac{23-28}{\sqrt{\frac{5^2}{25}+\frac{10^2}{30}}}}=-2.40  

4)What is the p-value for this hypothesis test?

Since is a bilateral test the p value would be:

p_v =2*P(z

5)Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the mean number of times men and women send a Twitter message in a day.

4 0
3 years ago
How do I get the brainliest answer?
eimsori [14]
After a certain amount of time whoever asked the question gets to pick who gave them the brainliest answer, so its up to whoever asked the question whether they think you deserve it!

6 0
4 years ago
Read 2 more answers
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