Answer:
phosphorus.
Explanation:
The atomic number of phosphorus is 15 so the protons will be 15.
The correct answer is D - When burning a log, the wood combined its components with oxygen. if you could capture the products (CO2, H2O, C, CO, etc), you would have a greater mass than what you started with, burning the log combined the log's components with oxygen in order to burn it.
H₂O would be the limiting reactant.
Balanced chemical equation:
6CO₂ + 6H₂O + light equation → C₆H₁₂O₆ + 6O₂
The amount of product that can be created is constrained by the reactant that is consumed first in a chemical reaction, commonly referred to as the limiting reactant (or limiting reagent).
Given
No. of moles of CO₂ = 18.6
Mass of H₂O = 2.38 × 10² g = 238g
No. of moles of H₂O = Given mass/ Molar mass
= 238 / 18 = 13.22 moles
Moles of H₂O = 13.22
According to the balanced chemical equation
6 moles of CO₂ react with 6 moles of H₂O
So the reactant that has less number of moles will be consumed first.
As the No. of moles of H₂O < No. of moles of CO₂
So, H₂O is the limiting reactant with 13.22 moles.
Hence, H₂O would be the limiting reactant.
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Answer:
5 seconds
Explanation:
Speed x Time. So t=ds. t=51=5.
Answer:
1. The oxidation half-reaction is: Mn(s) ⇄ Mn²⁺(aq) + 2e⁻
2. The reduction half-reaction is: Ag⁺(aq) + 1e⁻ ⇄ Ag(s)
Explanation:
Main reaction: 2Ag⁺(aq) + Mn(s) ⇄ 2Ag(s) + Mn²⁺(aq)
In the oxidation half reaction, the oxidation number increases:
Mn changes from 0, in the ground state to Mn²⁺.
The reduction half reaction occurs where the element decrease the oxidation number, because it is gaining electrons.
Silver changes from Ag⁺ to Ag.
1. The oxidation half-reaction is: Mn(s) ⇄ Mn²⁺(aq) + 2e⁻
2. The reduction half-reaction is: Ag⁺(aq) + 1e⁻ ⇄ Ag(s)
To balance the hole reaction, we need to multiply by 2, the second half reaction:
Mn(s) ⇄ Mn²⁺(aq) + 2e⁻
(Ag⁺(aq) + 1e⁻ ⇄ Ag(s)) . 2
2Ag⁺(aq) + 2e⁻ ⇄ 2Ag(s)
Now we sum, and we can cancel the electrons:
2Ag⁺(aq) + Mn(s) + 2e⁻ ⇄ 2Ag(s) + Mn²⁺(aq) + 2e⁻
