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enot [183]
3 years ago
13

A compound decomposes by a first-order process. if 25.0% of the compound decomposes in 60.0 minutes, the half-life of the compou

nd is _________.
a. 65 minutes
b. 198 minutes
c. 120 minutes
d. 145 minutes
e. 180 minutes
Chemistry
1 answer:
Tom [10]3 years ago
3 0
Answer:<span>d. 145 minutes
</span>
Half-life is the time needed for a radioactive to decay half of its weight. The formula to find the half-life would be:

Nt= N0 (1/2)^ t/h

Nt= the final mass
N0= the initial mass
t= time passed
h= half-life

If 25.0% of the compound decomposes that means the final mass would be 75% of initial mass. Then the half-live for the compound would be:
Nt= N0 (1/2)^ t/h
75%= 100% * (1/2)^ (60min/h)
3/4= 1/2^(60min/h)
log2 3/4 = log2 1/2^(60min/h)
0.41503749928 = -60min/h
h= -60 min / 0.41503749928= 144.6min 
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spin [16.1K]

Answer:

[H+] = 1.74 x 10⁻⁵

Explanation:

By definition pH = -log  [H+]

Therefore, given the pH,  all we have to do is  solve algebraically for  [H+] :

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6 0
4 years ago
What is the name for C2I3
Sidana [21]

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Explanation:

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The naming of covalent compound is given by:

The less electronegative element is written first.

The more electronegative element is written second. Then a suffix is added with it. The suffix added is '-ide'.

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4 0
3 years ago
At 393 K, the pressure of a sample of nitrogen is 1.07 atm. What will the pressure be at 478 K, assuming constant volume?
True [87]

Answer:

About 1.301 atm

Explanation:

The formula that you should is PV=nRT, where P stands for pressure, V stands for volume, n stands for the number of moles, R stands for the universal gas constant, and T stands for temperature in Kelvin. Since the volume, number of moles, and universal gas constant don't change, you don't need to worry about them.

1.07V=393nR

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P=1.301 atm. Hope this helps!

7 0
3 years ago
Taking a test please help. Thank you.
Komok [63]
It’s the 3rd one obviously bro
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3 years ago
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