Answer:
The structural formula of Compound C is <em>CH₂(CH)₅CH₃</em>.
Explanation:
Compound A is an <em>alkene</em> called Hexatriene, that is, it has three double bonds within its structure. Hydrogen atom is removed when compound A reacts with NaNH₂ in ammonia. Further reaction with iodomethane replaces the hydrogen atom with a methyl group from the iodomethane to form compound C.
Here is the step-wise mechanism:
CH₂(CH)₄CH₂ (With NaNH₂ in NH₃)...........> CH₂(CH)₄CH⁻ + H⁺
CH₂(CH)₄CH⁻ + CH₃I (Iodomethane) ...........> CH₂(CH)₅CH₃ + I⁻
Compound C is called 1, 3, 5-Heptatriene.
C) MgO aka magnesium oxide
Answer:
(a) 22.3 torr; 5.6 torr; (b) 27.9 torr; (c) 77.7 % heptane; 23.3 % octane
(d) Heptane is more volatile than octane
Explanation:
We can use Raoult's Law to solve this problem.
It states that the partial pressure of each component of an ideal mixture of liquids is equal to the vapour pressure of the pure component multiplied by its mole fraction. In symbols,
(a) Vapour pressure of each component
Let heptane be Component 1 and octane be Component 2.
(i) Moles of each component
(ii) Total moles
(iiii) Mole fractions of each component
(iv) Partial vapour pressures of each component
(b) Total pressure
(c) Mass percent of each component in vapour
The ratio of the mole fractions is the same as the ratio of the moles.
If we have 1 mol of vapour, we have 0.799 mol of heptane and 0.201 mol of octane
(d) Enrichment of vapour
The vapour is enriched in heptane because heptane is more volatile than octane.
Answer:
40.73 L.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm (P = 121.59 kPa/101.325 = 1.2 atm).
V is the volume of the gas in L (V = ??? L).
n is the no. of moles of the gas in mol (n = 2.0 mol).
R is the general gas constant (R = 0.082 L.atm/mol.K),
T is the temperature of the gas in K (T = 25°C + 273 = 298 K).
<em>∴ V = nRT/P</em> = (2.0 mol)(0.082 L.atm/mol.K)(298 K)/(1.2 atm) = <em>40.73 L.</em>