How many grams are in 3.80 mol of sodium chloride (NaCl)?

100 POINTS! PLEASE HELP! QUESTIONS ARE IN THE PICTURES. WILL GIVE BRAINLIEST, 5-STAR RATING, and THANKS. HALF-DONE ANSWERS WILL

Elenna [48]

Answer:

See Explanations....

Explanation:

NOTE => See attached graph.

1. 25-Turn Electromagnet

a. Strength of Batteries 1.5v vs 6.0v

6v:1.5v => 4:1 voltage ratio => That is, 6v battery is 4x voltage of 1.5v battery.

b. Ratio of Paperclips Picked Up

23clips(6v):6clips(1.5v) => 3.8clips(6v):1clip(1.5v)

That is, the 6 volt battery-EM picks up 3.8x more clips than the 1.5v battery-EM assuming constant number of coils given.

c. Empirical Relationship

From data given, an increase in voltage (V) produces a proportional increase in number of paperclips (C) picked up. Such is a Direct Relationahip between #Clips Picked Up and Battery Voltage.

Thus, C ∝ V => C = kV => k = C/V

Therefore, for k₁ = k₂ => C₁/V₁ = C₂/V₂

2. 50-Turn Electromagnet

a. Ratio of turns between electromagnets.

50-Turn EM : 25-Turn EM => 2:1 ratio of turns between electromagnets

b. Ratio of Paperclips Picked UP

Between maximum voltage and minimum voltages for 50-Turn EM

=> 47 clips (6v) : 13 clips (1.5v) => 3.6:1 ratio...

That is, the 6v battery-EM, on the average, picks up 3.6x more clips than the 1.5v battery-EM given 50-Turn EM.

3. Doubling number of coils:

Doubling the number of coils, on the average, doubles the number of clips picked up by either electromagnet.

Voltage 50-Turn EM 25-Turn EM Pick Up Ratio

1.5v 13 6 2:1

3.0v 26 12 2:1

4.5v 31 15.5 2:1

6.0v 47 23 2:1

4. Doubling Voltages:

Doubling voltage doubles the number of clips picked up by a given electromagnet regardless of the number of coils associated with magnet.

25-Turn EM Voltage Clips Pkd UP

1.5v 6

3.0v 12

Double voltage => Doubles # clips picked up*

50-Turn EM Voltage Clips Pkd UP

1.5v 13

3.0v 26

Double voltage => Doubles # clips picked up*

*Double Voltage => Double #clips picked up regardless of number of coil turns in electromagnet.

5. Predicting number of clips for 7.5v battery-EM

Using linear trendline equations shown on attached graphs...

#clips 50-Turn EM = 7.1333V + 2.5 = 7.1333(7.5) + 2.5 ≅ 56 clips

#clips 25-Turn EM = 3.6333V + 0.5 = 3.6333(7.5) + 0.5 ≅ 27 clips

Overall => 2:1 ratio of clips between 50-Turn EM and 25-Turn EM

6. Slope values based upon trendline equations shown on attached graphs are ...

25 Turn EM => slope = 3.6333

50 Turn EM => slope = 7.1333

Approximately a 2x increase upon doubling the number of coils of electromagnet.

Predicting number of clips for 1V electromagnets:

#Clips (1volt) 25-Turn EM = 3.6333(1) + 0.5 = 3.6833 ≅ 4 clips

#Clips (1volt) 50-Turn EM = 7.1333(1) + 2.5 = 9.6333 ≅ 10 clips

Shows to be consistent with double #clips with double number of coil turns.

6 0

3 years ago

An air sample consists of oxygen and nitrogen gas as major components. It also contains carbon dioxide and traces of some rare g

jekas [21]

Explanation:

A mixture is defined as the substance that contains two or more different number of substances that are physically mixed together.

For example, a mixture of air which contains oxygen, nitrogen and other gases.

A mixture in which solute particles are unevenly distributed into the solvent then it is known as a heterogeneous mixture.

For example, sand in water is a heterogeneous mixture.

A homogeneous mixture is defined as the mixture in which solute particles are evenly distributed in a solvent.

A homogeneous mixture is a clear solution.

For example, salt dissolved in water is a homogeneous mixture.

A solution is defined as the substance in which two or more substances are mixed together.

A compound is defined as the substance that contains two or more different elements that chemically combined together in a fixed ratio by mass.

A element is defined as the substance that contains only one type of atoms.

For example, a piece of sodium element will contain only atoms of sodium.

Whereas a pure substance is defined as the substance which contains only one type of molecule or one type of atom.

For example, $O_{2}$ , $N_{2}$ etc are pure substances.

Thus, we can conclude that the terms which could be used to describe the given sample of air is as follows.

pure chemical substance.

heterogenous mixture.

mixture.

4 0

3 years ago

How many formula units of silver fluoride, AgF, are equal to 42.15 g of this substance?

4vir4ik [10]

2.05 × 10²³ formula units

Given data:Mass of AgF = 43.15 gNumber of formula units = ?Solution:Number of moles of AgF:Number of moles = mass/ molar massNumber of moles = 43.15 g/ 126.87 g/molNumber of moles = 0.34 molNow Number of formula units will be determine by using Avogadro number.It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.The number 6.022 × 10²³ is called Avogadro number1 mole = 6.022 × 10²³ formula units0.34 mol × 6.022 × 10²³ formula units2.05 × 10²³ formula units

3 0

2 years ago

What are two main types of sedimentary rocks

Aleks [24]

Granite and pebbles are the answer

6 0

3 years ago

Read 2 more answers

An electron can be added to halogen atom to force a halide ion with

Lilit [14]

An electron can be added to halogen atom to force a halide ion with 8 valence electrons

An atom can be defined as the smallest part of an element which can take part in a chemical reaction.

However whenever, an electron is added to halogen atom to force a halide ion with 8 different valence electrons

So therefore; an electron can be added to halogen atom to force a halide ion with 8 valence electrons

Learn more about halogens:

brainly.com/question/18276987

#SPJ1

4 0

2 years ago