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KiRa [710]
3 years ago
12

I NEED ASAP!

Chemistry
2 answers:
Mnenie [13.5K]3 years ago
7 0

Answer:The correct answer is option B.

Explanation:

Mass of surcose dissolved = 50.0 g

volume of water = 1 L

Molarity=\frac{\text{Mass of sucrose}}{\text{molar mass of sucrose}\times \text{volume of solvent in L}}

Molarity=\frac{50.0 g}{342.3 g/mol\times 1 L}=0.1460 mol/L

Hence ,the correct answer is option B.

Levart [38]3 years ago
4 0
B 0.146m
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To standardize a hydrochloric acid solution, it was used as a titrant with a solid sample of sodium hydrogen carbonate, NaHCO3.
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As 1 mol of NaHCO₃ reacts with 1 mol of HCl, in 41.77 mL of the HCl solution there were 4.72x10⁻³ moles of HCl.

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