<span>We have a sample of a gas which is a compound of carbon and oxygen. Chemical analysis shows that it contains 2.4 g of carbon and 6.4 g of oxygen. What is its formula?</span>
B - CCL4
This is because it doesn't say Dicarbon or any of that sort, so Carbon is alone. This immediately eiminates the option of C.
A is incorrect as it has Chlorine first rather than Carbon, so that's also incorrect.
D is incorrect as 7 is hepta rather than tetra.
The list is as so;
Mono - 1; Di - 2; Tri - 3; Tetra - 4; Penta - 5; Hexa - 6; Hepta - 7; Octa - 8; Nona - 9; Deca - 10.
Hope this helps!
Answer:
Mass: 981.0 g
Density: 5.61 g/cm^3
Hardness: = 2.5 - 3
Unknown material: Chalcocite
Explanation:
Answer:
32.5 moles of O2(g) are necessaries for a complete reaction
Explanation:
Based on the reaction of combustion of C4H10(g):
C4H10(g) + 13/2 O2(g) → 4CO2(g) + 5H2O(g)
<em>1 mole of C4H10 needs 13/2 moles O2 for a complete reaction.</em>
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That means, the moles of O2 required for a reaction of 5.00 moles of C4H10 are:
5.00 moles C4H10 * (13/2mol O2 / 1mol C4H10) =
32.5 moles of O2(g) are necessaries for a complete reaction
