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Novay_Z [31]
3 years ago
13

What is the answer tox+5<-12

Mathematics
2 answers:
eimsori [14]3 years ago
4 0

Answer:

Step-by-step explanation:

x + 5 < -12

   -5      -5

x < -17

maxonik [38]3 years ago
3 0

Answer:

x < -17

Step-by-step explanation:

plz give me brainliest, I am 100% sure of the answer!!

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The graph of f(x) = (0.5)x is replaced by the graph of g(x) = (0.5)x − k. If g(x) is obtained by shifting f(x) down by 5 units,
tekilochka [14]

Answer: The value of k is 5 units.

Step-by-step explanation:

Since we have given that

The graph of f(x)=0.5x is replaced by the graph of g(x) = 0.5x-k

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Then the graph of f(x) = 0.5x is replaced by the graph of g(x) = 0.5x-5

Hence, k = 5 units

Therefore, the value of k is 5 units.

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My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
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