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Ad libitum [116K]
3 years ago
14

I'm stuck on number 4... help please?

Physics
2 answers:
lora16 [44]3 years ago
8 0
V= \frac{\Delta S}{\Delta t} = \frac{5}{15} = \frac{1}{3} m/s
Paha777 [63]3 years ago
3 0

Average <u>speed</u> = (distance covered) / (time to cover the distance) =
 
                                     (5m)  /  (15 sec) =

                                     (5/15) (m/s)  =  <em>1/3 m/s</em> .

Average <u>velocity</u> = 

         (displacement) / (time spent traveling)  in the direction of the displacement

Average velocity =  (5m) / (15 sec)  left =

                           (5/15) / (m/sec)  left  =

                               <em>1/3  m/s  left</em>.

A number without a direction is a speed, not a velocity.


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Answer:

The dimensionality of B is <em>length</em> per cubic <em>time</em>.

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Units for displacement and time are <em>length</em> [L] and <em>time</em> [T], respectively. Then, formula can be tested for dimensional analysis as follows:

[L] = B\cdot [T]^{3}

Now, let is clear B to determine its units:

B = \frac{[L]}{[T]^{3}}

The dimensionality of B is <em>length</em> per cubic <em>time</em>.

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3 years ago
Your code returns a number of 99.123456789 +0.00455679 for your calculation. How should you report it in your lab write-up?
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Answer: Your code returns a number of 99.123456789 +0.00455679

Ok, you must see where the error starts to affect your number.

In this case, is in the third decimal.

So you will write 99.123 +- 0.004 da da da.

But you must round your results. In the number you can see that after the 3 comes a 4, so the 3 stays as it is.

in the error, after the 4 comes a 5, so it rounds up.

So the final presentation will be 99.123 +- 0.005

you are discarding all the other decimals because the error "domains" them.

6 0
3 years ago
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