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Ad libitum [116K]
3 years ago
14

I'm stuck on number 4... help please?

Physics
2 answers:
lora16 [44]3 years ago
8 0
V= \frac{\Delta S}{\Delta t} = \frac{5}{15} = \frac{1}{3} m/s
Paha777 [63]3 years ago
3 0

Average <u>speed</u> = (distance covered) / (time to cover the distance) =
 
                                     (5m)  /  (15 sec) =

                                     (5/15) (m/s)  =  <em>1/3 m/s</em> .

Average <u>velocity</u> = 

         (displacement) / (time spent traveling)  in the direction of the displacement

Average velocity =  (5m) / (15 sec)  left =

                           (5/15) / (m/sec)  left  =

                               <em>1/3  m/s  left</em>.

A number without a direction is a speed, not a velocity.


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Wavelength is 0.5

Explanation:

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What type of fault creates huge mountains
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7 0
3 years ago
A skater is using very low friction rollerblades. A friend throws a Frisbee at her, on the straight line along which she is coas
kupik [55]

Answer:

a)  perfectly inelastic,  b)  collision is inelastic,  c)   elastic  

Explanation:

In this exercise, it is asked to identify what type of shock occurs between the skater and the frisbee, for this we must define a system formed by the skater and the fribee, so that the forces during the crash have been internal and the amount of movement is preserved

Initial instant. Before the skater touches the frisbee

    p₀ = M v₁ + m v₂

where M and m are the masses of the skater and frisbee, respectively

for the final moment they give us several possibilities, in all case the moment is conserved

       p₀ = p_{f}

case a)

Final instant. grabs the frisbee and holds it

    p_{f} = (M + m) v '

     p₀ = p_{f}

We can see that this shock is perfectly inelastic, it holds the fressbee

case b)

final instant.

This case is similar to the previous one, but the final speed of fresbee is zero, therefore this collision is inelastic and the kinetic energy is not conserved.

case c)

final instant. Grab the fressbee and resend it

      p_{f} = M v_{1f} + m v_{2f}

this is an elastic Shock since the equivalent of a rebound of the fressbee, the kinetic energy is conserved.

5 0
2 years ago
A seesaw is 4.0m long with a pivot at its midpoint. A boy who weighs 400N sits at a distance of 1.5m from the pivot. His sister
bezimeni [28]

Answer:

the girl must sit 2 cm from the pivot at the opposite end of the seesaw.

Explanation:

Given;

length of the seesaw, L = 4.0 m

weight of the boy, W₁ = 400 N

position of the boy from the pivot, d₁ = 1.5 m

weight of her sister, W₂ = 300 N

First, make a sketch of this information given;

                 0---0.5m---------------------Δ--------------------------4m

                         ↓<--------1.5m-------> <---------x--------->↓

                        400 N                                          300N

Apply the principle of moment about the pivot, to determine the value of x;

Sum of anticlockwise moment = sum of clockwise moment

400(1.5) = 300(x)

600 = 300x

x = 600/300

x = 2 cm

Thus, the girl must sit 2 cm from the pivot at the opposite end of the seesaw.

8 0
2 years ago
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