Answer:
The dimensionality of B is <em>length</em> per cubic <em>time</em>.
Explanation:
Units for displacement and time are <em>length</em>
and <em>time</em>
, respectively. Then, formula can be tested for dimensional analysis as follows:
![[L] = B\cdot [T]^{3}](https://tex.z-dn.net/?f=%5BL%5D%20%3D%20B%5Ccdot%20%5BT%5D%5E%7B3%7D)
Now, let is clear
to determine its units:
![B = \frac{[L]}{[T]^{3}}](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B%5BL%5D%7D%7B%5BT%5D%5E%7B3%7D%7D)
The dimensionality of B is <em>length</em> per cubic <em>time</em>.
It is A. Number of neutrons can differ with and be the same any given element.
Amber is the answer to this question
Answer:
Explanation:
Momentum is the mass of a moving body times its velocity. It can be transferred from one object to another
Answer: Your code returns a number of 99.123456789 +0.00455679
Ok, you must see where the error starts to affect your number.
In this case, is in the third decimal.
So you will write 99.123 +- 0.004 da da da.
But you must round your results. In the number you can see that after the 3 comes a 4, so the 3 stays as it is.
in the error, after the 4 comes a 5, so it rounds up.
So the final presentation will be 99.123 +- 0.005
you are discarding all the other decimals because the error "domains" them.