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Greeley [361]
3 years ago
6

The density of an object is

Chemistry
1 answer:
uysha [10]3 years ago
5 0

Answer:

Density is a measure of mass per unit of volume. Density is a measure of mass per volume. The average density of an object equals its total mass divided by its total volume.

I hope it helps.

Have a great day.

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Will the calculated Molarity of NaOH be too high or too low or unaffected if the following happen: when you answer the question,
vodomira [7]

Answer:

Explanation:

The result will be affected.

The mass of KHP  weighed out was used to calculate the moles of KHP weighed out (moles = mass/molar mass).

Not all the sample is actually KHP if the KHP is a little moist, so when mass was used to determine the moles of KHP, a higher number of moles than what is actually present would be obtained (because some of that mass was not KHP but it was assumed to be so. Therefore, there is actually a less present number of moles than the certain number that was thought of.

During the titration, NaOH reacts in a 1:1 ratio with KHP. So it was determined that there was the same number of moles of NaOH was the volume used as there were KHP in the mass that was weighed out. Since there was an overestimation in the moles of KHP, then there also would be an overestimation in the number of moles of NaOH.

Thus, NaOH will appear at a higher concentration than it actually is.

7 0
4 years ago
What is the mass of carbon dioxide formed when 36g of carbon is burnt?<br> C+O2 -------&gt;C02
Anestetic [448]

Answer:

Mass = 132 g

Explanation:

Given data:

Mass of CO₂ formed = ?

Mass of C burnt = 36 g

Solution:

Chemical equation:

C + O₂    →    CO₂

Number of moles of carbon:

Number of moles = mass/molar mass

Number of moles = 36 g/ 12 g/mol

Number of moles = 3 mol

now we will compare the moles of carbon and carbon dioxide.

                C           :        CO₂

                 1           :         1

                3           :         3

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 3 mol × 44 g/mol

Mass = 132 g

7 0
3 years ago
You leave for school late when you are pulled over by a police officer for speeding. He clocks you at 52 mi/hr . What is your sp
yawa3891 [41]

Answer:

Explanation:

The maximum speed limit in Prince Edward Island

unless otherwise posted is 80 kilometres per hour

(km/h). The basic speed limits are:

• 40 km/h (25 mph) in most municipalities

(municipalities may establish the maximum

speed limit within their boundaries);

• 50 km/h (30 mph) in urban areas;

• 60 km/h (40 mph) in school zones designated as

such by the erection of signs at the entrance and

the exit, between 8 a.m. and 5 p.m. when

children are present on or near the highway on

school days;

• 80 km/h (50 mph) on most provincial highways;

and

• 90 km/h (55 mph) on the TransCanada and

other designated highways.

Posted speed limits indicate the maximum safe

speed under favourable driving conditions.

3 0
4 years ago
If you were to conduct an experiment to answer the question, "Does the volume of a caffeinated drink affect your reaction time?”
Ann [662]

Answer:

A Type of Drink

Explanation:

A controlled variable remains constant throughout the experiment.

In such experiment, you'd test the volume of one single caffeinated drink. You'd have to use the same type of drink every trial.

4 0
3 years ago
Concentration data is commonly monitored during a reaction to determine the order with respect to a reactant. Consider the types
kirill115 [55]

Answer:

1) first order

2) second order

3) zero order

Explanation:

The curve of a first order reaction shows it to be exponential. In fact for a first order reaction, the concentration at a time t is an exponential function;

[A]t= [Ao] e^-kt

Where

[A]t = concentration at time =t

[Ao]= initial concentration

k= rate constant

t= time

For a second order reaction, the rate of reaction is directly proportional to the concentration of reactants.

For zero order reactions, rate of reaction is independent of concentration hence rate = k(rate constant)

3 0
3 years ago
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