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marin [14]
3 years ago
9

A student used 1.168g of an unknown weak acid and titrated it against 28.75 mL of 0.105M NaOH to reach the equivalence point. Wh

at is the molar mass of his unknown acid
Chemistry
1 answer:
Vaselesa [24]3 years ago
3 0

Answer:

The molar mass of the unknown acid is 386.8 g/mol

Explanation:

Step 1: Data given

Mass of the weak acid = 1.168 grams

volume of NaOH = 28.75 mL = 0.02875 L

Molarity of NaOH = 0.105 M

Since we only know 1 equivalence point, we suppose the acid is monoprotic

Step 2: Calculate moles NaOH

Moles NaOH = molarity NaOH * volume NaOH

Moles NaOH = 0.105 M * 0.02875 L

Moles NaOH = 0.00302 moles

We need 0.00302 moles of weak acid to neutralize the NaOH

Step 3: Calculate molar mass of weak acid

Molar mass = mass / moles

Molar mass = 1.168 grams / 0.00302 moles

Molar mass = 386.8 g/mol

The molar mass of the unknown acid is 386.8 g/mol

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A 10kg bowling ball would require what force to accelerate down an alleyway at a rate of 3m/s2?
mixas84 [53]
Ok so this all boils down to Newton's second law

Force = mass X acceleration 

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8 0
3 years ago
Sadiq repeated the experiment by adding sulphuric acid to magnesium carbonate. Write the word equation for this reaction below:
anygoal [31]

Answer:

Sulphuric acid + Magnesium Carbonate → Magnesium sulphate + carbon dioxide + water

Explanation:

Sulphuric acid + Magnesium Carbonate

The products are;

Magnesium sulphate, carbon dioxide and water

MgCO3 (s) + H2SO4 (aq) → MgSO4 (aq) + CO2 (g) + H2O (l)

Word Equation;

Sulphuric acid + Magnesium Carbonate → Magnesium sulphate + carbon dioxide + water

7 0
3 years ago
The irreversible elementary gas-phase reaction is carried out isothermally at 305 K in a packed-bed reactor with 100 kg of catal
tamaranim1 [39]

Answer:

0.856.

Explanation:

Lets represent the irreversible elementary gas phase equation of reaction as

A + B -----------------------------------> C + D

We have that the percentage of conversion is 80%.

The pressure, p from the ratio of exit pressure and entering pressure is p = 2/20 = 1/10 = 0.1.

Therefore, n = 1 - p^2/ weight of the catalyst = 1 - 0.1^2/ 100 = 9.9 × 10^-3 kg cat^-.

Now, let's make use of the equation below;

J/ 1 - J = kb^2/ u [ w - nw^2/2] ----------(1).

0.8 / 1- 0.8 = k ( 0.4)^2/ 10 [ 100 - (9.9× 10^-3 × 100^2/ 2] .

k = 4.95 dm^6/ kg.cat .mol.min

The turbulent flow= 1/2 × 9.9 × 10^-3 = 4.95 × 10^-3 kg cat^-.

Thus, making use of the equation (1) again, we have that;

{4.95 × 10^-3 × 0.4}/ 10 × [ 100 - (4.95 × 10^-3 × 100^2)] / 2 = 5.964.

Therefore, a/1 - a = 5.964.

5.964( 1 - a) = a.

5.964 - 5.964a = a.

5.964 = a + 5.964a.

5.964 = 6.964a.

a = 5.964/ 6.964 = 0.856.

5 0
2 years ago
12.Calculate the wavelength of an object moving with a velocity of 5 x105 m s-1
uranmaximum [27]

Answer:

Wavelength, \lambda=3.3\times 10^{-18}\ m

Explanation:

We have,

Velocity of the object, v=5\times 10^5\ m/s

Mass of the object, m=4\times 10^{-22}\ kg

It is required to find the wavelength of the object. The relation between wavelength and velocity of the object is given by :

\lambda=\dfrac{h}{mv}

h is Planck's constant

\lambda=\dfrac{6.6\times 10^{-34}}{4\times 10^{-22}\times 5\times 10^5}\\\\\lambda=3.3\times 10^{-18}\ m

So, the wavelength of the object is 3.3\times 10^{-18}\ m.      

5 0
3 years ago
Can anybody help please
romanna [79]

Answer:

Three hydrogen atoms

6 0
2 years ago
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