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It shouldn't have any lone pairs since it is a tetrahedral structure. Ge has 4 valence electrons. Each H has 1 valence electron. Therefore, each H valence electron will pair with each valence electron on Ge.
The answer is 79.9 g.
Copper takes 92.0% of aluminum bronze and it is a limiting factor. We have aluminum in excess, so we need to make a proportion.
If 73.5 g of copper are 92.0%, how many g of aluminum bronze will be 100%:
73.5 g : 92.0% = x : 100%.
x = 73.5 g : 100% * 92.0%
x = 79.9 g
Therefore, from 73.5 g of copper and 6.4 g of aluminum (since 79.9 g - 73.5 g = 6.4 g), maximum 79.9 g of aluminum bronze can be prepared.
Answer:
Explanation: The answer is A. logging
Answer:
3.33 mol
Explanation:
1 g of oxygen is 0.062502343837894 mol
53.3 * 0.062502343837894
3.3313749265597505 mol
