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malfutka [58]
3 years ago
6

How many significant figures are in 0.05?

Chemistry
1 answer:
drek231 [11]3 years ago
3 0
There is one significant figure 
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A sample of sulfur hexafluoride gas occupies a volume of 5.10 L at 198 ºC. Assuming that the pressure remains constant, what tem
Ludmilka [50]

Answer:

When the volume will be reduced to 2.50 L, the temperature will be reduced to a temperature of 230.9K

Explanation:

Step 1: Data given

A sample of sulfur hexafluoride gas occupies a volume of 5.10 L

Temperature = 198 °C = 471 K

The volume will be reduced to 2.50 L

Step 2 Calculate the new temperature via Charles' law

V1/T2 = V2/T2

⇒with V1 = the initial volume of sulfur hexafluoride gas = 5.10 L

⇒with T1 = the initial temperature of sulfur hexafluoride gas = 471 K

⇒with V2 = the reduced volume of the gas = 2.50 L

⇒with T2 = the new temperature = TO BE DETERMINED

5.10 L / 471 K = 2.50 L / T2

T2 = 2.50 L / (5.10 L / 471 K)

T2 = 230.9 K = -42.1

When the volume will be reduced to 2.50 L, the temperature will be reduced to a temperature of 230.9K

8 0
3 years ago
8.5ml of a sample of sea water solution was added to a 44.317g evaporating dish the combination weighted 52.987g after evaporati
Ratling [72]

Answer:  There is no question, but we can calculate a couple of items:

Density of sea water sample = (52.987g-44.317g)/8.5ml

Inorganic content of sample (mostly salts) = (44.599g-44.317g)/(52.987g-44.317g) x 100% = percent inorganics in water sample

Explanation:

5 0
3 years ago
23g of sodium reacted with 35.5g og chlorine calculate the mass of the sodium chloride formed. Help!
Simora [160]
Hope this helps you.

4 0
3 years ago
What type of chemical bond holds the na+ and cl- ions together in table salt?
fredd [130]

<em>The bond between Na + and Cl- ions is an ionic bond</em>

<em>To achieve stability, atoms with low ionization energy such as Na atoms will release electrons and bind to atoms with high-affinity energy such as Cl atoms</em>

\boxed{\boxed{\bold{Further~explanation}}}

Atoms have different stability. Unstable atomic atoms will try to form stable electron configurations like those of noble gases. Where noble gases have the number of outer electrons 2 or 8

The formation of electron configurations such as noble gases can be done by forming shared ions or electron pairs

Atoms with high ionization energy and atoms that are difficult to draw electrons will form bonds with shared electron pairs (electrons can be from one atom or two atoms attached)

In forming ions, atoms will release or attract electrons

Ion bonds occur because atoms that have low ionization energy (easily release electrons) form a + ion, and these electrons are bound by atoms that have large affinity energy (easily pulling electrons)

Generally, ionic bonds occur in metal and nonmetallic elements. Metal elements have low ionization energy and non-metallic elements have a high electron affinity

In Na atoms, to achieve stability, Na will release one electron so that it has an electron configuration like noble gas Ne

Na: 2 8 1

Ne: 2 8

so that it becomes a Na + ion

While the Cl atom will bind one electron, so it has an electron configuration like noble gas Ar

Cl: 2 8 7

Ar: 2 8 8

So that it becomes a Cl- ion

Finally, there will be an attractive attraction between positive ions and negative ions and NaCl is formed

So the bond between Na + and Cl- ions is an ionic bond

\boxed{\boxed{\bold{Learn~more}}}

the octet rule

brainly.com/question/6979933

a noble gas

brainly.com/question/1349717

brainly.com/question/3505291

ionic bonds and covalent bonds

brainly.com/question/2092388

Keywords: ionic and covalent bonds, the octet rule, noble gases, electron configurations

4 0
3 years ago
Read 2 more answers
How many moles of water are produced when 3.45 moles of KMnO4 react? Give your answer to the nearest 0.1 moles. moles H2O
andrew11 [14]

Answer:

13.8 moles of water produced.

Explanation:

Given data:

Moles of KMnO₄ = 3.45 mol

Moles of water = ?

Solution:

Chemical equation:

16HCl + 2KMnO₄ → 2KCl + 2MnCl₂ + 5Cl₂ + 8H₂O

Moler ratio of water and KMnO₄:

             KMnO₄       :        H₂O

                2             :          8

               3.45         :         8/2×3.45 = 13.8 mol

Hence, 3.45 moles of KMnO₄ will produced 13.8 mol of water.

7 0
3 years ago
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