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yanalaym [24]
3 years ago
10

How do I solve these two?

Mathematics
1 answer:
Bas_tet [7]3 years ago
8 0

Answer:

1.D

2.B

Step-by-step explanation:

For the first one divide see which one is less which is D

For the second one Ive always used the method kcf keep change flip so you keep \frac{15}{1} the change ÷ to multiplication so then flip \frac{2}{9} so the equation would be

\frac{15}{1}x\frac{9}{2} so multiply the 15 by 9 then you get 135 then divide by 2 so thats your answer

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I NEED HELP ASAP WITH THIS QUESTION.
GalinKa [24]

Answer:

a.) equivilent to;     4 x 7x - 4 x 6         and         28x-24

b.) equivilent to;     8y + 13y          and            21y

Step-by-step explanation:

A.)

4(7x-6)     First you have to multiply everything in the parenthesis by 4 because of distribution

7x x 4 - 6 x 4                That is why it is equivilent to the  4 x 7x - 4 x 6  awnser

28x - 24                    That is the end result by simplifiying and show why it is equivient to 28x-24

B.)

8y+6y+7y                 Simplify the like terms

8y+13y                   6+7 is 13 so that is why it is eauals to 8y+13y

21y                       if you continue adding you see why it equals 21y

4 0
4 years ago
Explain how you know that 70 is greater than 1/3 but less than three 2/3
nadya68 [22]
No 70 is greater than both 1/3 and 2/3 because 1/3 = 33.333 and 2/3 = 66.666

Hope i will be the brainliest person
8 0
3 years ago
Is anyone good at this? Please help me!
liubo4ka [24]

Answer:

Step-by-step explanation:

For a function given as,

f(x)= 2x + 2

Domain of the given function is → {-5, -1, 2, 3}

For the Range of the given function,

f(-5) = 2(-5) + 2

      = -8

f(-1) = 2(-1) + 2

      = -2 + 2

      = 0

f(2) = 2(2) + 2

     = 6

f(3) = 2(3) + 2

     = 8

Therefore, set for the range will be → {-8, 0, 6, 8}

Now plot the ordered pairs on the graph,

(-5, -8), (-1, 0), (2, 6), (3, 8)

5 0
3 years ago
U=k<br> /a , for a <br> i need help on finding a in that question
irina1246 [14]

Answer:

Create a single variable linear equation that has no solution. Solve the equation algebraically to prove that it does not have a solution.

Create a single variable linear equation that has one solution. Solve the equation algebraically to prove that there is one distinct solution for the equation.

Create a single variable linear equation that has infinitely many solutions. Solve the equation algebraically to prove that there is an infinite number of solutions for the equation

Step-by-step explanation:

3 0
3 years ago
I need help asap plz
leva [86]

Answer: it’s C

Step-by-step explanation: because my teacher told me

4 0
3 years ago
Read 2 more answers
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