Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
In plain and short, what's 2/3 of 7/8? well, is just their product.
A. The range is equal to the highest value minus the lowest value. Since the table given in part A is already in terms of range, then there is no need for a solution. The range of temperature for each month is as it is.
B. For this question, find the largest value which would represent the all-time high. That would be on February at 95°F. The lowest value would also represent the all-time low. That would be on July at 50°F.
C. The range of part B is just the difference of the all-time high and all-time low temperatures.
Range = 95°F - 50°F = 45°F
Answer:
Step-by-step explanation:
h(g(x))
g(x)= 3x + 1
h(3x + 1) = 4(3x + 1) = 12x + 4
3x - 4y = 9 and 2x + 3y = 7, which of the following would be the best method?