Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is
Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,
Putting the given values, we get
Therefore, the area of 4 walls of the room is 54 sq. metres.
To solve for the other leg, you need to use Pythagorean theory.
The theory states that C^2 = A^2 + B^2
In your case, you have to solve for B.
C = 40 (hypotenuse) A = 24 (leg 1)
The formula rewritten for B is
Now, you can solve.
Therefore, B = 32.
So the second leg is 32 feet.
ANSWER
672cm²
EXPLANATION
The area of a regular hexagon is given by the formula,
where a=14cm is the apothem and p=96cm is the perimeter of the regular hexagon.
We substitute the values into the formula,
Therefore the approximate area of the hexagon is 672cm²
Answer:
Step-by-step explanation:
<h3><u>(2x - 5)(4x - 3)</u></h3>
The AC method, also known as splitting the middle, can be shown like this:
8x^2 - 26x + 15
<em><u>Check factors of 120.</u></em>
1 * 120
-1 * -120
2 * 60
-2 * -60
3 * 40
-3 * -40
5 * 24
-5 * -24
6 * 20
-6 * -20 (these factors, when added together, are equal to the middle term, and thus splitting the middle term is possible.)
<em><u>Split the middle term.</u></em>
8x^2 - 6x - 20x + 15
<em><u>Group in terms of 2.</u></em>
(8x^2 - 6x) - (20x + 15)
<em><u>Factor each binomial.</u></em>
2x(4x - 3) - 5(4x - 3)
<em><u>Rearrange the terms.</u></em>
(2x - 5)(4x - 3)
