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Nadusha1986 [10]
3 years ago
6

Implement the function:

Computers and Technology
1 answer:
Sloan [31]3 years ago
3 0

Answer:

This is written in C++

Check comments for explanations

Program starts here

#include<iostream>

#include<string>

using namespace std;

//The function get_ap_terms begins here

string get_ap_terms(int a, int d, int size_tn)

{  

// This line initializes the expected string to empty string

string result = "";

//The for iteration loops through the number of terms the function is expected to return

for(int i = 1; i<= size_tn;i++)

{

//This line checks if the loop is less than the number of  terms    

if(i < size_tn)

  {

//This string gets the current term of the progression

   result+=to_string(a)+ ", ";

//This line calculates the next term

   a+=d;  

  }

  else

  {

//This line calculates the last term

   result+=to_string(a);

  }

}

//This line returns the string containing the first n terms of the arithmetic progression

return result;

}

//The main function starts here

int main()

{

//This line declares the first term (a), the common difference (d) and the number of terms (size_tn)

int a,d,size_tn;

//This line prompts the user for the first term

cout<<"First Term: ";

//This line gets the first term

cin>>a;

//This line prompts the user for the common difference

cout<<"Common Difference: ";

//This line gets the common difference

cin>>d;

//This line prompts the user for number of terms

cout<<"Number of Terms: ";

//This line gets the number of terms

cin>>size_tn;

//This line calls the function to print the string containing the first n terms

cout<<get_ap_terms(a, d, size_tn);

return 0;

}

//Program ends here

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7 0
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URGENT!
lutik1710 [3]

<u>Explanation:</u>

Hey there! you need not to panic about it ,your program didn't have Driver program i.e main program! the correct & working code is given below:

// C++ program to count  even digits  in a given number .

#include <iostream>  

using namespace std;  

// Function to count digits

int countEven(int n)  

{  

int even_count = 0;    

while (n > 0)  

{  

 int rem = n % 10;  

 if (rem % 2 == 0)  

  even_count++;  

 n = n / 10;  

}  

cout << "Even count : "

 << even_count;  

if (even_count % 2 == 0 )  

 return 1;  

else

 return 0;  

}  

// Driver Code  

int main()  

{  

int n;  

std::cin >>n;

int t = countEven(n);  

return 0;  

}  

6 0
3 years ago
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