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3 years ago

How does it change when it is brought inside a warm house?

Chemistry

2 answers:

netineya [11]3 years ago

8 0

How does what change ?

Dafna1 [17]3 years ago

3 0

What specifically are you talking about?

You might be interested in

An element's atomic number is 78. How many protons would an atom of this element have?

Oksanka [162]

Answer:

Explanation:

atomic number is number of protons

6 0

4 years ago

Calculate ΔH for the reaction: C(graphite) + 2H 2(g) + 1/2 O 2(g) => CH 3OH(l) Using the following information: C(graphite) +

Alika [10]

Answer:

$\Delta H$ for the given reaction is -238.7 kJ

Explanation:

The given reaction can be written as summation of three elementary steps such as:

$C(graphite)+O_{2}(g)\rightarrow CO_{2}(g)$ $\Delta H_{1}= -393.5 kJ$

$2H_{2}(g)+O_{2}(g)\rightarrow 2H_{2}O(l)$ $\Delta H_{2}= (2\times -285.8)kJ$

$CO_{2}(g)+2H_{2}O(l)\rightarrow CH_{3}OH(l)+\frac{3}{2}O_{2}(g)$ $\Delta H_{3}= 726.4 kJ$

---------------------------------------------------------------------------------------------------

$C(graphite)+2H_{2}(g)+\frac{1}{2}O_{2}(g)\rightarrow CH_{3}OH(l)$

$\Delta H=\Delta H_{1}+\Delta H_{2}+\Delta H_{3}=-238.7 kJ$

4 0

4 years ago

Recovery standards are a necessary tool for determining exactly how much of a particular analyte you are able to extract from a

Dafna11 [192]

Answer:

2.05mg Fe/ g sample

Explanation:

In all chemical extractions you lose analyte. Recovery standards are a way to know how many analyte you lose.

In the problem you recover 3.5mg Fe / 1.0101g sample: 3.465mg Fe / g sample. As real concentration of the standard is 4.0 mg / g of sample the percent of recovery extraction is:

3.465 / 4×100 = 86,6%

As the recovery of your sample was 1.7mg Fe / 0.9582g, the Iron present in your sample is:

1.7mg Fe / 0.9582g sample× (100/86.6) = 2.05mg Fe / g sample

I hope it helps!

5 0

3 years ago

Question 22 A VHF television station assigned to channel transmits its signal using radio waves with a frequency of . Calculate

aleksklad [387]

The question is incomplete, here is the complete question:

A VHF television station assigned to channel transmits its signal using radio waves with a frequency of 66.0 MHz. Calculate the wavelength of the radio waves. Round your answer to 3 significant digits.

Answer: The wavelength of the radio waves is 4.54 m

Explanation:

To calculate the wavelength of light, we use the equation:

$\lambda=\frac{c}{\nu}$

where,

$\lambda$ = wavelength of the light

c = speed of light = $3\times 10^8m/s$

$\nu$ = frequency of light = $66.0MHz=66.0\times 10^6s^{-1}$

Putting the values in above equation, we get:

$\lambda=\frac{3\times 10^8m/s}{66.0\times 10^{6}s^{-1}}=4.54m$

Hence, the wavelength of the radio waves is 4.54 m

6 0

4 years ago

What is wrong with the structures that you obtain using the incorrect arrows?

Liono4ka [1.6K]

-A bromine with an incomplete octet and a positive charge.
-A bromine with an incomplete octet and a positive charge and an oxygen with ten valence electrons and two charges.
-A compound with the bond between a bromine and an oxygen with three bonds.

7 0

4 years ago