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olchik [2.2K]
3 years ago
10

The phase of matter can be changed by:

Chemistry
2 answers:
Bond [772]3 years ago
7 0

Answer:

1. Increasing temperature

Explanation:

Hope this helps.

Natali5045456 [20]3 years ago
3 0
1. Increasing the temperature
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This question has multiple parts. Work all the parts to get the most points. An aqueous antifreeze solution is 39.0% ethylene gl
nlexa [21]

Answer:

Molality = <u>10.300 m</u>

<u>Molarity = 6.5970 M</u>

<u>mole fraction = </u>0.156549

Explanation:

39.0 % = ethylene glycol

61.0 % = water

imagine the total mass = 100g

39.0% ethylene glycol = 39g

61.0 % water = 61g

1) Molality = number of moles / mass of solvent (kg)

Molar mass of ethylene glycol = 62.07g/mole

mole = 39g / 62.07g/mole = 0.6283 moles

Molality = moles / mass of solvent = 0.6283 moles / 0.061kg = <u>10.300 m</u>

<u />

<u>2) Molarity</u> = number of moles / volume of solution

Since we know the density  of the solution = 1.05g /ml

⇒ volume = 100g / 1.05g /mL   = 95.24 mL = 0.09524 L

Molarity = 0.6283 moles / 0.09524 L = <u>6.5970 M</u>

3) Mole fraction

moles water = 61g / 18.02g/mole  = 3.38513 moles

Total number of moles = moles of ethylene glycol + moles of water = 0.6283 + 3.38513 = 4.0134276 moles

Mole fraction = 0.6283/ 4.0134276 = 0.156549

3 0
2 years ago
Boyles Law P1V1 = P2V2
arsen [322]

Answer:

A. The balloons will increase to twice their original volume.

Explanation:

Boyle's law states that the pressure exerted on a gas is inversely proportional to the volume occupied by the gas at constant temperature. That is:

P ∝ 1/V

P = k/V

PV = k (constant)

P = pressure, V = volume.

P_1V_1=P_2V_2

Let the initial pressure of the balloon be P, i.e. P_1=P, initial volume be V, i.e. V_1=V. The pressure is then halved, i.e. P_2=\frac{P}{2}

P_1V_1=P_2V_2\\\\P*V=\frac{P}{2} *V_2\\\\V_2=\frac{2*P*V}{P}\\\\V_2=2V

Therefore the balloon volume will increase to twice their original volume.

3 0
2 years ago
What is the five physical properties
tester [92]

image: http://cf.ydcdn.net/1.0.1.69/images/searchclear.png

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13.6K
SHARES
HOMEREFERENCEEXAMPLESEXAMPLES OF PHYSICAL PROPERTIES
Examples of Physical Properties
7th grade8th grade9th gradeMiddle SchoolHigh SchoolCollege
image: http://www.yourdictionary.com/index.php/image/articles/18915.ThinkstockPhotos-83110393_boomerang.jpg


A physical property is any property of matter or energy that can be measured. It is an attribute of matter that can be observed or perceived.

Common Physical Properties
Absorption of electromagnetic - The way a photon’s energy is taken up by matter
Absorption (physical) - Absorption between two forms of matter
Albedo - Reflecting power of a surface
Angular momentum - The amount of rotation of an object
Area - Amount of a two dimensional surface in a plane
Brittleness - Tendency of a material to break under stress
Boiling point - Temperature where a liquid forms vapor
Capacitance - Ability of an object to store an electrical charge
Color - Hue of an object as perceived by humans
Concentration - Amount of one substance in a mixture
Density - Mass per unit volume of a substance
Dielectric constant - Storage and dissipation of electric and magnetic energy
Ductility - Ability of a substance to be stretched into a wire
Distribution - Number of particles per unit volume in single-particle phase space
Efficacy - Capacity to produce an effect
Elasticity - Tendency of a material to return to its former shape
Electric charge - Positive or negative electric charge of matter
Electrical conductivity - A material's ability to conduct electricity
Electrical impedance - Ratio of voltage to AC
Electrical resistivity - How strongly a flow of electric current is opposed
Electric field - Made by electrically charged particles and time-varying magnetic fields.
Electric potential - Potential energy of a charged particle divided by the charge
Emission - Spectrum of frequencies of electromagnetic radiation emitted
Flexibility - Pliability
Flow rate - Amount of fluid which passes through a surface per unit time.
Fluidity - Flows easily
Freezing point - Temperature where a liquid solidifies
Frequency - Number of repetitions in a given time frame
Hardness - How resistant solid matter is to external force
Inductance - When the current changes, the conductor creates voltage
Intrinsic impedance - Ratio of electric and magnetic fields in an electromagnetic wave
Intensity - Power transferred per unit area
Irradiance - Power of electromagnetic radiation per unit area
Length - Longest dimension of an object
Location - Place where something exists
Luminance - Amount of light that passes through a given area
Luminescence - Emission of light not resulting from heat
Luster - The way light interacts with the surface of a crystal, mineral or rock
Malleability - Ability to form a thin sheet by hammering or rolling a material
Magnetic moment - Force that the magnet exerts on electric currents and the torque that a magnetic field exerts on it
Mass - An object's resistance to being accelerated
Melting point - Temperature where a solid changes to a liquid
Momentum - Product of the mass and velocity of an object
Permeability - Ability of a material to support a magnetic field
Smell - Scent or odor of a substance
Solubility - Ability of a substance to dissolve
Specific heat - Heat capacity per unit mass of a material
Temperature - Numerical measure of heat and cold
Thermal conductivity - Property of a material to conduct heat
Velocity - Rate of change in the position of an object
Viscosity - Resistance to deformation by stress
Volume - Space that a substance occupies

6 0
3 years ago
Read 2 more answers
0.32 g of a walnut is burned under an aluminum can filled with 58.1 mL of water. The water temperature in the can increases by 3
balu736 [363]

Answer:

1.8 × 10² cal

Explanation:

When 0.32 g of a walnut is burned, the heat released is absorbed by water and used to raise its temperature. We can calculate this heat (Q) using the following expression.

Q = c × m × ΔT

where,

c: specific heat capacity of water

m: mass of water

ΔT: change in the temperature

Considering the density of water is 1 g/mL, 58.1 mL = 58.1 g.

Q = c × m × ΔT

Q = (1 cal/g.°C) × 58.1 g × 3.1°C

Q = 1.8 × 10² cal

3 0
3 years ago
Which electron has a higher probability of being found at 4 Å of the nucleus, one in a 2s orbital or one in a 2p orbital?
Lena [83]

Answer:

one in a 2s orbital

Explanation:

Because of the peak near the nucleus in the 2s curve there is a higher probability of finding a 2s within 4 Å of the nucleus. In a multi-electron atom an electron in a 2s orbital will have a lower energy than one in a 2p orbital

4 0
3 years ago
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