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2 years ago

How many neutrons does this atom have?

Chemistry

2 answers:

Marizza181 [45]2 years ago

8 0

Answer:

the ander is B. 6 neurons

Vinil7 [7]2 years ago

7 0

Answer:

Explanation:

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If 0.507J of heat leads to a 0.007 degree C change in water, what mass is present?

Mamont248 [21]

Answer:

17.3 g

Explanation:

<u>Given the following data;</u>

Quantity of heat, Q = 0.507 J
Temperature = 0.007°C
Specific heat capacity of water = 4.2 J/g°C

Mathematically, Heat capacity is given by the formula;

$Q = MCT$

Where;

Q represents the heat capacity or quantity of heat.
M represents the mass of an object.
C represents the specific heat capacity of water.
T represents the temperature.

Making "M" the subject of formula, we have;

$M = \frac {Q}{CT}$

Substituting the values into the formula, we have;

$M = \frac {0.507}{4.2*0.007}$

$M = \frac {0.507}{0.0294}$

<em>Mass, m = 17.3 grams</em>

8 0

2 years ago

Kostya randomly chooses a number from 1 to 10. What is the probability he chooses a number less than 5?

Ghella [55]

A. 1/2

Explanation- There is a 5/10 chance of choosing on of the numbers which simplifies to 1/2

3 0

2 years ago

Read 2 more answers

Which of the following is an organic moleclue ?

Doss [256]

Answer:

water

Explanation:

6 0

2 years ago

A 13 g sample of P4010 contains how many

Alex777 [14]

Answer:

$\large \boxed{5.5 \times 10^{22}\text{ molecules of P$_{2}$O}_{5}}$

Explanation:

You must calculate the moles of P₄O₁₀, convert to moles of P₂O₅, then convert to molecules of P₂O₅.

1. Moles of P₄O₁₀

$\text{Moles of P$_{4}$O}_{10} = \text{13 g P$_{4}$O}_{10} \times \dfrac{\text{1 mol P$_{4}$O}_{10}}{\text{283.89 g P$_{4}$O}_{10}} = \text{0.0458 mol P$_{4}$O}_{10}$

2. Moles of P₂O₅

P₄O₁₀ ⟶ 2P₂O₅

The molar ratio is 2 mol P₂O₅:1 mol P₄O₁₀

$\text{Moles of P$_{2}$O}_{5} = \text{0.0458 mol P$_{4}$O}_{10} \times \dfrac{\text{2 mol P$_{2}$O}_{5}}{\text{1 mol P$_{4}$O}_{10}} = \text{0.0916 mol P$_{2}$O}_{5}$

3. Molecules of P₂O₅

$\text{No. of molecules} = \text{0.0916 mol P$_{2}$O}_{5} \times \dfrac{6.022 \times 10^{23}\text{ molecules P$_{2}$O}_{5}}{\text{1 mol P$_{2}$O}_{5}}\\\\= \mathbf{5.5 \times 10^{22}}\textbf{ molecules P$_{2}$O}_{5}\\\text{There are $\large \boxed{\mathbf{5.5 \times 10^{22}}\textbf{ molecules of P$_{2}$O}_{5}}$}$

6 0

3 years ago

Textbook mass 2000 grams volume 4000cm3 density

PIT_PIT [208]

Density = mass/volume = 2000/4000 = 0.5 grams/cm3. Hope this hopes!

8 0

3 years ago