The mass of oxygen gas is released in the reaction of decomposition of magnesium oxide 6.4 grams
calculation
mass of oxygen=mass of magnesium oxide -mass of magnesium produced
that is 16.12-9.72=6.4 grams
1.75 moles of copper must react to form 3.50 moles of silver metal.
Explanation:
Answer:
V₂ = 4.00 L
Explanation:
Given that:
Volume (v1) = 6.00 L
Temperature (T1) = 300 K
Pressure (P1) = 1.00 atm
VOlume (V2) = unknown???
Temperature (T2) = 600 K
Pressure (P2) = 3.00 atm
Using combined gas law equation:
200 = 50V₂
V₂ = 200/50
V₂ = 4.00 L
In chemistry, if you want to express the amount of a substance out of the total amount, you express it in concentration. There are numerous units of measurement: molarity, molality, normality, mass percentages, volume percentage, or a mix of both. For this problem, the unit used for concentration is in mass percentages. The formula would be
Percentage Concentration = [(Actual Amount of Substance)/(Total amount of all substances)] * 100
Since we are given with the total mass of all the substances in the ocean and the percentage concentration, the only missing information is the actual amount of Na+ in the ocean. Substituting the values:
1.076 = (Amount of Na+ /1.8×10²¹ kg)*100
Amount of Na+ = 1.9368×10¹⁹ kg
