Explanation:
The given data is as follows.
Resistance (R) = 1200 ohm, Area (A) = 
m (as 
)
Diameter (d) = 2.3 mm = 
m
First, we will calculate the length as follows.
R = 
Here, 
= resistivity of aluminium = 
Putting the given values above and we will calculate the value of length as follows.
R =
1200 = 
L = 
As the circumference of circular wire = 
or, = 
= 
And, number of turns will be calculated as follows.
No. of turns × Circumference = Length of wire
No. of turns × 
= 
Thus, we can conclude that turns of wire are needed.
Answer:
We begin by solving the equation P = hρg for depth h: h=Pρg h = P ρ g . Then we take P to be 1.00 atm and ρ to be the density of the water that creates the pressure.
Buildings can affect the surface albedo.
The surface is the outermost or uppermost layer of a physical item or area. it is the element or place of the object which could first be perceived by an observer through the usage of the senses of sight and contact and is the component with which other materials first engage.
A surface is the outermost layer of any physical object. it is the part of the object that may be perceived by an observer using their experience of sight and touch and is the portion with which surrounding substances first engage.
The chemical and mechanical residences include chemical composition, grain, hardness, energy, and inhomogeneities.
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<span>6.20 m/s^2
The rocket is being accelerated towards the earth by gravity which has a value of 9.8 m/s^2. Given the total mass of the rocket, the gravitational drag will be
9.8 m/s^2 * 5.00 x 10^5 kg = 4.9 x 10^6 kg m/s^2 = 4.9 x 10^6 N
Add in the atmospheric drag and you get
4.90 x 10^6 N + 4.50 x 10^6 N = 9.4 x 10^6 N
Now subtract that total drag from the thrust available.
1.250 x 10^7 - 9.4 x 10^6 = 12.50 x 10^6 - 9.4 x 10^6 = 3.10 x 10^6 N
So we have an effective thrust of 3.10 x 10^6 N working against a mass of 5.00 x 10^5 kg. We also have N which is (kg m)/s^2 and kg. The unit we wish to end up with is m/s^2 so that indicates we need to divide the thrust by the mass. So
3.10 x 10^6 (kg m)/s^2 / 5.00 x 10^5 kg = 0.62 x 10^1 m/s^2 = 6.2 m/s^2
Since we have only 3 significant figures in our data, the answer is 6.20 m/s^2</span>
The portions of the electromagnetic spectrum are used in the television set. It is used in the picture tube in the old television set.
<h3>What is the electromagnetic spectrum ?</h3>
The electromagnetic radiation distribution in accordance with the frequency or wavelength is known as the electromagnetic spectrum.
The portions of the electromagnetic spectrum are used in the television set. It is used in the picture tube in the old television set.
Hence, option b is correct.
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