Answer:
3.913x10^22 atoms
Explanation:
We have come to discover that 1 mole of any substance contains 6.02x10^23 atoms as explained by Avogadro's hypothesis.
This means that 1 mole of Hg contains 6.02x10^23 atoms.
Therefore, 0.065 moles of Hg will contain = 0.065 x 6.02x10^23 = 3.913x10^22 atoms
Answer:
2 KCIO₃ → 2 KCI + 3 O₂
Explanation:
A chemical equation is balanced when the number of atoms of each element is equal on both sides of the equation.
You have already identified the initial number of atoms of each element on both sides of the equation. As a rule of thumb, we balance the number of oxygen and hydrogen atoms last.
However, since all the other elements are already balanced, we shall start by balancing the number of oxygen atoms.
The lowest common multiple of 2 and 3 is 6. Thus, we shall ensure that both sides of the equation has 6 oxygen atoms.
2 KCIO₃ → KCI + 3 O₂
<u>Reactants</u>
K --- 2
C--- 2
I --- 2
O --- 6
<u>Products</u>
K --- 1
C --- 1
I --- 1
O --- 6
Notice that number of K, C and I atoms on the left-hand side of the equation has also changed.
2 KCIO₃ → 2 KCI + 3 O₂
<u>Reactants</u>
K --- 2
C --- 2
I --- 2
O --- 6
<u>Products</u>
K --- 2
C --- 2
I --- 2
O --- 6
The equation is now balanced.
Answer:
true
Explanation:
The lighter a gas is, the faster it will effuse; the heavier a gas is, the slower it will effuse. Of all the choices, helium (He) has the lowest molecular weight (atomic weight in this case), so it will have the highest rate of effusion.
1. inner core
2. outer core
3. mantle
4.crust
Answer: P2 = 0.858 atm
Explanation:
Use the combined gas law: P1V1/T1 = P2V2/T2,
where the subscripts are the initial (1) and final (2) states. Temperature must be in Kelvin. We want P2, so rearrange the equation to solve for P2:
P2 = P1(V1/V2)(T2/T1)
Note how I've arranged the volume and temperature values: as ratios. Now it is easy to cancel units and see what is going to happen to the pressure if we lower the temperature. Since the pressure change is a function of (T2/T1), and we are lowering the temperature (T2), we'd expect this to decrease the pressure.
No information is given on volume, so we'll assume a convenient value of 1 liter. Now enter the data:
P2 = (0.917atm)*(1)*(322K/344K)
P2 = 0.858 atm
