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3 years ago

N__________ is the study of atoms.

Chemistry

2 answers:

denpristay [2]3 years ago

4 0

I think it is nuclues

AlekseyPX3 years ago

3 0

I think the answer might be nuclear physics

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determine the rate of a reaction that follows the rate law: rate=k[A]m[B]n, where: k= 1x10-2 [A]=2 M B= 3 M m=2 n=1?

victus00 [196]

Answer:

0.12 molL‐¹ s‐¹

Explanation:

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3 years ago

Lil give brainly 20 points

torisob [31]

Answer: i would say producer

Explanation:

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2 years ago

Read 2 more answers

Classify each of these reactions. A single reaction may fit more than one classification. Ba ( ClO 3 ) 2 ⟶ BaCl 2 + 3 O 2 Ba(ClO

Lena [83]

Answer: a) $Ba(ClO_3)_2\rightarrow BaCl_2+3O_2$ : Decomposition

b) $NaNO_2+HCl\rightarrow NaCl+HNO_2$ : double displacement

c) $CaO+CO_2\rightarrow CaCO_3$ : Synthesis (Combination)

d) $ZnSO_4+Mg\rightarrow MgSO_4+Zn$ : redox

Explanation:

Decomposition is a type of chemical reaction in which one reactant gives two or more than two products.

$Ba(ClO_3)_2\rightarrow BaCl_2+3O_2$

A double displacement reaction is one in which exchange of ions take place.

$NaNO_2+HCl\rightarrow NaCl+HNO_2$

Synthesis reaction is a chemical reaction in which two reactants are combining to form one product.

$CaO+CO_2\rightarrow CaCO_3$

Redox reaction is a type of chemical reaction in which oxidation and reduction takes place in one single reaction. The oxidation number of one element increases and the oxidation number of other element decreases.

$ZnSO_4+Mg\rightarrow MgSO_4+Zn$

4 0

3 years ago

To grow or reach the next stage in a life cycle is to develop.

gogolik [260]

Answer:

It's obviously true

Explanation:

As we have evolved over the years we have become more advanced

5 0

3 years ago

Let us write the appropriate equilibria and associate the correction <img src="https://tex.z-dn.net/?f=K_b" id="TexFormula1" tit

rosijanka [135]

Explanation:

The relation between $K_a\&K_b$ is given by :

$K_w=K_a\times K_b$

Where :

$K_w=1\times 10^{-14}$ = Ionic prodcut of water

The value of the first ionization constant of sodium sulfite = $K_{a1}=1.4\times 10^{-2}$

The value of $K_{b1}$ :

$1\times 10^{-14}=1.4\times 10^{-2}\times K_{b1}$

$K_{b1}=\frac{1\times 10^{-14}}{1.4\times 10^{-2}}=7.1\times 10^{-13}$

The value of the second ionization constant of sodium sulfite = $K_{a2}=6.3\times 10^{-8}$

The value of $K_{b2}$ :

$1\times 10^{-14}=6.3\times 10^{-8}\times K_{b1}$

$K_{b1}=\frac{1\times 10^{-14}}{6.3\times 10^{-8}}=1.6\times 10^{-7}$

3 0

3 years ago