The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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$192 divided by 12 is 16 so 16 x 3 is 48. That is your answer $48. Your welcome bud.
We can take prime numbers so they don't have a common factor other than 1.
3, and 5.
So we have to list the multiples to find the LCM
3: 3, 6, 9, 12,
15, 18
5: 5, 10,
15, 20, 25
15 is the LCM of 3 and 5
So, you can notice that if two numbers, lets call them a and b, have no common factor, then

is the LCM.
Hope that helped :)
I think it'd be x=4 but I'm not 100% sure
Obtuse angle................................