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Yuliya22 [10]
2 years ago
6

How many moles of N2 are in a flask with a volume of 0.5 L at a pressure of 400.0 kPa and a temperature of 300.0 K?

Chemistry
1 answer:
mylen [45]2 years ago
5 0

Answer:

0.08moles

Explanation:

Given parameters:

Volume of gas  = 0.5L

Pressure of gas  = 400kPa

Temperature of gas  = 300K

Unknown:

Number of moles of N₂ = ?

Solution:

Applying the ideal gas law which is a combination of the three gas law: Boyle's law, Charles's law and Avogadro's law will solve this problem.

The ideal gas law is stated as;

              PV  = nRT

P is the pressure of the gas

V is the volume of the gas

n is the number of moles

R is the gas constant

T is the temperature of the gas

  We need to convert kPa of the pressure to atm which is a more comfortable unit to work with.

      400kPa will be \frac{400}{101.325}   = 3.95atm

Input the variables in the equation;

             3.95 x 0.5  = n x 0.082 x 300

                            n  = 0.08moles

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Answer:

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Explanation:

Let's consider the following reaction.

A(g) + 2B(g) ⇄ C(g) + D(g)

We can find the pressures at equilibrium using an ICE chart.

       A(g) + 2 B(g) ⇄ C(g) + D(g)

I       1.00     1.00        0        0

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E    1.00-x  1.00-2x     x         x

The pressure at equilibrium of C is 0.211 atm, so x = 0.211.

The pressures at equilibrium are:

pA = 1.00-x = 1.00-0.211 = 0.789 atm

pB = 1.00-2x = 1.00-2(0.211) = 0.578 atm

pC = x = 0.211 atm

pD = x = 0.211 atm

The pressure equilibrium constant (Kp) is:

Kp = pC × pD / pA × pB²

Kp = 0.211 × 0.211 / 0.789 × 0.578²

Kp = 0.169

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