How many moles of N2 are in a flask with a volume of 0.5 L at a pressure of 400.0 kPa and a temperature of 300.0 K?
1 answer:
Answer:
0.08moles
Explanation:
Given parameters:
Volume of gas = 0.5L
Pressure of gas = 400kPa
Temperature of gas = 300K
Unknown:
Number of moles of N₂ = ?
Solution:
Applying the ideal gas law which is a combination of the three gas law: Boyle's law, Charles's law and Avogadro's law will solve this problem.
The ideal gas law is stated as;
PV = nRT
P is the pressure of the gas
V is the volume of the gas
n is the number of moles
R is the gas constant
T is the temperature of the gas
We need to convert kPa of the pressure to atm which is a more comfortable unit to work with.
400kPa will be = 3.95atm
Input the variables in the equation;
3.95 x 0.5 = n x 0.082 x 300
n = 0.08moles
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194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.
Explanation:
In order to convert the given number of molecules of BCl₃ to grams, first we have to convert the molecules to moles.
It is known that 1 moles of any element has 6.022×10²³ molecules.
Then 1 molecule will have moles.
So
Thus, 1.66 moles are included in BCl₃.
Then in order to convert it from moles to grams, we have to multiply it with the molecular mass of the compound.
As it is known as 1 mole contains molecular mass of the compound.
As the molecular mass of BCl₃ will be
Mass of boron is 10.811 g and the mass of chlorine is 35.453 g.
Molar mass of BCl₃ = 10.811+(3×35.453)=117.17 g.
So, 194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.