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Y_Kistochka [10]
3 years ago
10

Write or show a complete formation of the following ionic compounds a)sodium oxide (Na2O)​

Chemistry
1 answer:
OLga [1]3 years ago
3 0

Answer:

Na + O2 -> Na2O

Explanation:

sodium has one atom, oxygen has two atoms and so they exchange atoms hence Sodium obtaining two atoms at the end of the formation

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Gnesinka [82]

Answer:

The answer will be A

Explanation:

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2 years ago
Which power source uses the earth’s internal heat?
Nataly_w [17]

Answer:

Its geothermal energy.

Explanation:

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3 years ago
What are the 7 methods of separating mixtures?​
Gennadij [26K]

Methods Of Separating Mixtures

Handpicking.

Threshing.

Winnowing.

Sieving.

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Separating Funnel.

3 0
3 years ago
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Nistu is cooking rice in a pot. When she leaves the pot on the stove for a while, the temperature of the rice increases. What ha
Mila [183]

Answer:

Their average kinetic energy increases

Explanation:

The average kinetic energy of the rice molecules increases as the pot is left on the cooking stove.

Heat is transferred to the pot by conduction from the heat source. The heat is then transferred to the rice in the cooking pot by convection.

  • As the water in the pot heats up.
  • The rice gains thermal energy.
  • This causes the molecules of the rice particles to start vibrating.
  • As the molecules vibrate about their fixed position, their thermal energy continues to increase.
  • Therefore, the amount of heat absorbed by the rice increases with time and this actually cooks the food.
5 0
3 years ago
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If 8.00 g NH4NO3 is dissolved in 1000 g of water, the water decreases in temperature from 21.00 degrees Celsius to 20.39 degrees
telo118 [61]

Answer:

25.7 kJ/mol

Explanation:

There are two heats involved.

heat of solution of NH₄NO₃ + heat from water = 0

q₁  +  q₂  =  0

n  =  moles of NH₄NO₃  =  8.00 g NH₄NO₃  ×  1 mol NH₄NO₃/80.0 g NH₄NO₃          

∴ n =   0.100 mol NH₄NO₃

q₁ = n * ΔHsoln = 0.100 mol * ΔHsoln

m  =  mass of solution  =  1000.0 g + 8.00 g  =  1008.0 g

q₂  =  mcΔT  = 58.0 g  ×  4.184 J°C⁻¹  g⁻¹  × ((20.39-21)°C) = -2570.19 J

q₁  +  q₂  =  0.100 mol  ×ΔHsoln  – 2570.19 J  =  0

ΔHsoln  =  +2570.19 J  /0.100 mol  =  +25702 J/mol  =  +25.7 kJ/mol

7 0
3 years ago
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