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Natali5045456 [20]
3 years ago
14

Help me please asap!

Mathematics
1 answer:
Blizzard [7]3 years ago
8 0

4 · x^4 · x^4 · y

4 x^8 y

In words: four times x to the eighth times y

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What are the vertex, focus, and directrix of the parabola with the equation x2+8x+4y+4=0
Novay_Z [31]
<span>x2 +8x +4y +4 = 0
</span>4y=<span> -x2 -8x -4</span>y = -.25*x^2 -2x -1
a = -.25b = -2c = -1
x position of vertex:
h = -b / 2a
h = 2 / 2*-.25h = 2 / -.5h = -4
y position of vertex:
k = ah^2 + bh + ck = -.25*-4^2 + -2*-4 + -1k = -4 +8 -1k = 3
VERTEX = (-4, 3)**************************************************************************
x value of focus =x value of vertex = -4
y value of focus =(1 (-b^2 -4ac)) / 4a

a = -.25 b = -2 c =-1
y value = (1 (-4 -4*-.25*-1)) / 4*-.25
y value = (1 (-4 -4*-.25*-1)) / -1
y value = (1 -4 +1) / -1y value = (-2 / -1)y value = 2
focus value = (-4, 2)
Answer is the last one.

7 0
3 years ago
For nitrogen to be a liquid, its temperature must be within 12.78 °F of –333.22 °F. The equation |x + 333.22 | = 12.78 can be us
MrRissso [65]

Answer:

Yes

I hoped this helped

6 0
2 years ago
What is the equation of a circle with a center located at (-3, 4) and a diameter of 14?
AnnZ [28]

Answer: (x + 3)^2 + (y - 4)^2 = 49

Step-by-step explanation:

The equation of a circle given the center and radius: (x - h)^2 + (y - k)^2 = r^2

Given: center (-3,4) ; h = -3 and k = 4

diameter = 14

To find the radius: divide the diameter by 2 = 14/2 = 7 = r

Center: (-3,4) and radius: 7

Equation of a circle: (x - h)^2 + (y - k) ^2 = r^2

Substitute h = -3, k = 4, r = 7

(x - (-3))^2 + (y - 4)^2 = 7^2

Answer:

Equation of the circle: (x + 3)^2 + (y - 4)^2 = 49

7 0
3 years ago
There is a photo attached<br><br>tan 270 is incorrect!
wlad13 [49]

\dfrac{1-\cos135^\circ}{\sin135^\circ}=\dfrac{1-\left(\cos^2 67.5^\circ-\sin^2 67.5^\circ\right)}{2\sin67.5^\circ\cos67.5^\circ}=\dfrac{1-\left(1-\sin^2 67.5^\circ-\sin^2 67.5^\circ\right)}{2\sin67.5^\circ\cos67.5^\circ}=\medskip\\=\dfrac{2\sin^2 67.5^\circ}{2\sin67.5^\circ\cos67.5^\circ}=\dfrac{\sin 67.5^\circ}{\cos 67.5^\circ}=\tan 67.5^\circ

3 0
3 years ago
(2x - y + 3) (2x - y - 3)using identities ​
Tems11 [23]

Step-by-step explanation:

(2x-y+3)(2x-y-3)=

4x²-2xy-6x-2xy+y²+3y+6x-3y-9=

4x²-4xy+y²-9=

(2x-y)²-9

6 0
3 years ago
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