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3 years ago

Find the value of x in the triangle shown below.

Mathematics

1 answer:

Sindrei [870]3 years ago

8 0

Answer:

x=5

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 +b^2 = c^2 where a and b are the legs and c is the hypotenuse

12^2 +x^2 = 13^2

144 +x^2 = 169

Subtract 144 from each side

144-144 +x^2 = 169-144

x^2 =25

Take the square root of each side

sqrt(x^2) = sqrt(25)

x = 5

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2 years ago

What are the solution(s) of x2-4-0?

Elanso [62]

Answer:

For $x^2 - 4 = 0$ , x = 2, or x = - 2.

Step-by-step explanation:

Here, the given expression is :

$x^2 - 4 = 0$

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3 years ago

Read 2 more answers