3 years ago

The fact that something is magnetic can be determined by watching its what?

1 answer:

6 0

You can check if something is magnetic by watching if it's attracted/repelled by a magnet.

That's the same as saying that the fact that something is magnetic can be determined by watching its behavior.

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A child blows a leaf from rest straight up in the air. The leaf has a constant upward acceleration of magnitude 1.0\,\dfrac{\tex

Novosadov [1.4K]

Answer:

Explanation:

Given

Acceleration a = 1.0m/s²

Displacement S = 1.0m

Required

Time t taken by the leaf to displace

Using the equation of motion

S = ut+1/2at²

Substitute

1.0 = 0+1/2(1)t²

1 = t²/2

Cross multiply

t² = 2

t = ±√2

t = 1.41secs

It takes the leaf to 1.41s to displace by 1m upward

6 0

4 years ago

How do I solve for time if I have initial velocity and final speed?

xeze [42]

Final speed = initial speed + (acceleration x time)

(final speed - initial speed) = acceleration x time

Time = (final speed - initial speed) / acceleration

4 0

3 years ago

you travel an average speed of 20 km/h in a straight line to get to your grandmothers house. it takes you 3 hours to get to her

alexira [117]

6.6 miles I think hope this is the right answer.

7 0

3 years ago

a charge Q exerts a 2.4 N force on another charge q.If the distance between the charges is doubled,what is the magnitude of the

GrogVix [38]

Heyyyyyyyyyy how is your day goingggg luvvvv

6 0

3 years ago

A car travels along a horizontal road which is an arc of radius 125m. the greatest speed at which the car can travel without sle

hammer [34]

The coefficient of friction between the Tyre and the ground is 0.11

<u>Explanation:</u>

Given:

Radius of the track (r)=125 m.

Speed with which the car travels (v) =42 km/hr

=11.67 m/s

To Find:

Coefficient of friction between the Tyre and the ground.

Formula to be used:

$Centripetal\ force\ Fc= mv^2/r\\\\=m\times 11.67^2/125\\\\=1.08 m$

We know that,Frictional force is equal to centripetal force

Frictional force=μmg

therefore 1.08 m=μmg

Cancelling "m" on both sides we get,

μ=1.08/g=1.08/9.8

=0.11

Thus the coefficient of friction between the Tyre and the ground is 0.11

7 0

3 years ago