Answer:
Explanation:
Given
Acceleration a = 1.0m/s²
Displacement S = 1.0m
Required
Time t taken by the leaf to displace
Using the equation of motion
S = ut+1/2at²
Substitute
1.0 = 0+1/2(1)t²
1 = t²/2
Cross multiply
t² = 2
t = ±√2
t = 1.41secs
It takes the leaf to 1.41s to displace by 1m upward
Final speed = initial speed + (acceleration x time)
(final speed - initial speed) = acceleration x time
Time = (final speed - initial speed) / acceleration
6.6 miles I think hope this is the right answer.
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The coefficient of friction between the Tyre and the ground is 0.11
<u>Explanation:</u>
Given:
Radius of the track (r)=125 m.
Speed with which the car travels (v) =42 km/hr
=11.67 m/s
To Find:
Coefficient of friction between the Tyre and the ground.
Formula to be used:

We know that,Frictional force is equal to centripetal force
Frictional force=μmg
therefore 1.08 m=μmg
Cancelling "m" on both sides we get,
μ=1.08/g=1.08/9.8
=0.11
Thus the coefficient of friction between the Tyre and the ground is 0.11