The coefficient of friction between the Tyre and the ground is 0.11
<u>Explanation:</u>
Given:
Radius of the track (r)=125 m.
Speed with which the car travels (v) =42 km/hr
=11.67 m/s
To Find:
Coefficient of friction between the Tyre and the ground.
Formula to be used:
We know that,Frictional force is equal to centripetal force
Frictional force=μmg
therefore 1.08 m=μmg
Cancelling "m" on both sides we get,
μ=1.08/g=1.08/9.8
=0.11
Thus the coefficient of friction between the Tyre and the ground is 0.11
Answer:
The angle that the door must rotate is 70.5 graus
Explanation:
When the door rotates through and angel X, the magnetic flux that passes through the door decreases from its maximum value to 0.3 of its maximum value
This way,
X = 0.3 Xmax
X = B A cosX = 0.3 B A
or
cosX = 0.3
or
X = (0.3) = 70.5
X = 70.5 graus