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3 years ago

How do I solve for time if I have initial velocity and final speed?

1 answer:

4 0

Final speed = initial speed + (acceleration x time)

(final speed - initial speed) = acceleration x time

Time = (final speed - initial speed) / acceleration

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Is anyone good with 9-10th grade physics?? Please pm me I have a few questions.

Tcecarenko [31]

Let's give it a whirl .....

3 0

3 years ago

The radius of the earth's very nearly circular orbit around the sun is 1.5 1011 m. find the magnitude of the earth's velocity, a

kotykmax [81]

The radius of Earth's circular trajectory is
$R=1.5*10^{11} m$
The time for the Earth to travel around the Sun is
$t=365(days)*24(hours)*3600(seconds) =3.1536*10^7 (s)$
Thus the velocity is velocity
$v=2\pi R/t =2\pi *1.5*10^{11}/(3.1536*10^{7})=2.99*10^4 (m/s)$
From this we can deduce the centripetal acceleration
$a=v^2/R =(2.99*10^4)^2/(1.5*10^{11}) =5.96*10^{-3} (m/s^2)$
Angular velocity is
$\omega =v/R =(2.99*10^4)/(1.5*10^{11})=2*10^{-7} (rad/s)$

5 0

4 years ago

Learning Task No. 5 Identify the word or words being described by each statement. Choose y box below. 1. It is the process of ch

Rashid [163]

Identifying the word that is described by each statements in the question is listed below:

Evaporation
Transpiration
Hydrosphere
Water Cycle
Condensation

<h3>Meaning of Water </h3>

Water can be simply defined as any fluid or substance that is odurless, colorless and tasteless.

Water is a very important factor and substance that sustains life in humans and plants on earth.

Water tends to undergo different changes and processes in plant, animals and even as a substance on its own

In conclusion the above listed processes are all related to water.

Learn more about Water: brainly.com/question/1313076

#SPJ1

4 0

2 years ago

An electron is accelrated by a unifor electric field (1000v/m) pointing vertically upward. Use energy methods to get the magnitu

ExtremeBDS [4]

Explanation:

In the given situation two forces are working. These are:

1) Electric force (acting in the downward direction) = qE

2) weight (acting in the downward direction) = mg

Therefore, work done by all the forces = change in kinetic energy

Hence, $qE \times S + mg \times S = 0.5 \times mv^{2}$

$1.6 \times 10^{-19} \times 1000 + 9.1 \times 10^{-31} \times 9.8 \times (\frac{0.10}{100}) = 0.5 \times 9.1 \times 10^{-31} \times v^{2}$

It is known that the weight of electron is far less compared to electric force. Therefore, we can neglect the weight and the above equation will be as follows.

$(1.6 \times 10^{-19} \times 1000) \times (\frac{0.10}{100}) = 0.5 \times 9.1 \times 10^{-31} \times v^{2
}$

v = $sqrt{\frac{1.6 \times 10^{-19}}{(0.5 \times 9.1 \times 10^{-31})}$

= 592999 m/s

Since, the electron is travelling downwards it means that it looses the potential energy.

8 0

3 years ago

Calculate the current flowing if a charge of 36 kilocoulombs flows in 1 hour.

kupik [55]

Answer:

2hrs and some mins

Explanation:

bc 2×36= 17 =)

3 0

3 years ago