Answer:
Spring constant, k = 24.1 N/m
Explanation:
Given that,
Weight of the object, W = 2.45 N
Time period of oscillation of simple harmonic motion, T = 0.64 s
To find,
Spring constant of the spring.
Solution,
In case of simple harmonic motion, the time period of oscillation is given by :
![T=2\pi\sqrt{\dfrac{m}{k}}](https://tex.z-dn.net/?f=T%3D2%5Cpi%5Csqrt%7B%5Cdfrac%7Bm%7D%7Bk%7D%7D)
m is the mass of object
![m=\dfrac{W}{g}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7BW%7D%7Bg%7D)
![m=\dfrac{2.45}{9.8}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7B2.45%7D%7B9.8%7D)
m = 0.25 kg
![k=\dfrac{4\pi^2m}{T^2}](https://tex.z-dn.net/?f=k%3D%5Cdfrac%7B4%5Cpi%5E2m%7D%7BT%5E2%7D)
![k=\dfrac{4\pi^2\times 0.25}{(0.64)^2}](https://tex.z-dn.net/?f=k%3D%5Cdfrac%7B4%5Cpi%5E2%5Ctimes%200.25%7D%7B%280.64%29%5E2%7D)
k = 24.09 N/m
or
k = 24.11 N/m
So, the spring constant of the spring is 24.1 N/m.
The amount of solid does not affect how you are describing the solid so a is the answer