Given:
Consider the below figure attached with this question.
∠EFH = (5x + 1)°, ∠HFG = 62°, and ∠EFG = (18x + 11)°
To find:
The measure of ∠EFH.
Solution:
From the figure it is clear that ∠EFG is divide in two parts ∠EFH and ∠HFG. So,



Isolate variable terms.


Divide both sides by 13.


The value of x is 4.




Therefore, the measure of ∠EFH is 21°.
7 should be the answer.
7 doubled is 14. Hope this helps
Answer:
3/3 is equivilant to 1.
Multiplying 6/4 by 1, would be 6/4. Also, multiplying 6/4 by 3/3 would be 18/12, which could be simplified to 6/4.
Hope this helps!