Answer:
s=1/2at²+v(initial)t
s=1/2(3)(30)²+(0)(30)
s=1/2(3)(30)²+0
s=900(1/2)(3)
s=450(3)
s=1350m
Explanation: -is this what your looking for?
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I guess 48 , but I’m not sure
In position #1, at time t₁ = 0, the coordinates are (1.1 m, 3.4 m).
That is,
x₁ = 1.1 m, y₁ = 3.4 m.
In position #2, at time t₂ = 3.0 s, the coordinates are (5.3 m, -0.5 m).
That is,
x₂ = 5.3 m, y₂ = -0.5 m.
The x-component of the average velocity is
Vx = (x₂ - x₁)/(t₂ - t₁)
= (5.3 - 1.1 m)/(3 - 0 s)
= 1.4 m/s
Similarly, the y-component of the average velocity is
Vy = (-0.5 - 3.4)/3
= -1.3 m/s
Answer
The x and y components of the average velocity are 1.4 m/s and -1.3 m/s respectively.
Answer: Two children are riding on a marry-go-round. Child A is at a greater distance from the axis of rotation than child B. Thus, the child A, located at a greater distance from the axis of rotation have a larger tangential speed.
Explanation: To find the correct answer we have to know more about the Angular velocity of a rotating body.
<h3>What is the angular velocity?</h3>
- In rotational motion, the angular velocity ω can be defined as, the change in angular displacement(Ф) per unit time (t).
- It's the revolution per second.
- The angular velocity can be expressed in terms of the tangential velocity as well as the radius of the circular path as,
![w=V/r](https://tex.z-dn.net/?f=w%3DV%2Fr)
<h3>
How to solve the question?</h3>
- We know that the expression for the tangential velocity as,
![V=wr](https://tex.z-dn.net/?f=V%3Dwr)
- In the question, for both the child, the value of w will be same. Thus, the only quantity that depends on the tangential velocity will be the distance from the axis of rotation.
- The maximum will the value of V, if the r maximizes.
- Thus, child A with greater distance will have larger tangential speed.
Thus, we can conclude that, child A with greater distance will have larger tangential speed.
Learn more about the Angular velocity here:
brainly.com/question/28019892
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<u>Velocity here =displacement /time take</u>
<u>v=45-33/3</u>
<u>v=12/3</u>
<u>v=4 m/s</u>