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Svetradugi [14.3K]
3 years ago
8

You walk from a position 33 m to a position 45 m in 3 seconds. What is your velocity?

Physics
2 answers:
enyata [817]3 years ago
6 0

<u>Velocity here =displacement /time take</u>

<u>v=45-33/3</u>

<u>v=12/3</u>

<u>v=4 m/s</u>

vladimir2022 [97]3 years ago
4 0

Your average velocity is 4 m/s in the direction from the first position to the second one.

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Answer:

18750 kg-m/s

Explanation:

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2 years ago
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The rocket is fired vertically and tracked by the radar station shown. When θ reaches 66°, other corresponding measurements give
Flauer [41]

Answer:

velocity = 1527.52 ft/s

Acceleration = 80.13 ft/s²

Explanation:

We are given;

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Angular velocity; ω = θ˙˙ = 0.019 rad/s

Also, angle θ reaches 66°

So, velocity of the rocket for the given position will be;

v = rθ˙˙/cos θ

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v = 1527.52 ft/s

Acceleration is given by the formula ;

a = a_r/sinθ

For the given position,

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Thus,

a = (r¨ - r(θ˙˙)²)/sinθ

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4 0
2 years ago
In 1865, Jules Verne proposed sending men to the Moon by firing a space capsule from a 220-m-long cannon with final speed of 10.
Sidana [21]

Answer:

The unrealistically large acceleration experienced by the space travelers during their launch is 2.7 x 10⁵ m/s².

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s = 220 m

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he unrealistically large acceleration experienced by the space travelers during their launch

vf² = v₀²+2as, v₀ = 0

vf² = 2as

a =vf²/2s

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Compare your answer with the free-fall acceleration

a/g = 2.7 x 10⁵/9.8

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3 years ago
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true if you are refering to the desing of the experimnt as it does identify the variable

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