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ivanzaharov [21]
3 years ago
15

Light of wavelength 630 nm falls on two slits and produces an interference pattern in which the third-order bright red fringe is

45 mm from the central fringe on a screen 3.0 m away. What is the separation of the two slits?
Physics
1 answer:
goblinko [34]3 years ago
6 0

Answer:

d \frac{x}{l} = m×  λ⇒ d = λ ×m×l / x

= 630×10^{-9} m × 3×3m/ 45×10^{-3} m

= 1.26×10^{-4}m

Explanation:

the above calculation is based on Young’s double slit experiment where the two slits provide two coherent light sources which results either constructive interference or destructive interference when passing through a double slit.

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Answer:

n=2.9\times 10^9

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Explanation:

Given that

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Lets take total number of tube is n

Q= n q

n=Q/q

n=\dfrac{0.083\times 10^{-3} }{ 2.8\times 10^{-14}}

n=2.9\times 10^9

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