Question

Two children are riding on a merry-go-round. Child A is at a greater distance from the axis of rotation than child B. Which child has the larger tangential speed

Answer 1

Answer: Two children are riding on a marry-go-round. Child A is at a greater distance from the axis of rotation than child B. Thus, the child A, located at a greater distance from the axis of rotation have a larger tangential speed.

Explanation: To find the correct answer we have to know more about the Angular velocity of a rotating body.

What is the angular velocity?

• In rotational motion, the angular velocity ω can be defined as, the change in angular displacement(Ф) per unit time (t).
• It's the revolution per second.
• The angular velocity can be expressed in terms of the tangential velocity as well as the radius of the circular path as,

                              $w=V/r$

How to solve the question?

• We know that the expression for the tangential velocity as,

                               $V=wr$

• In the question, for both the child, the value of w will be same. Thus, the only quantity that depends on the tangential velocity will be the distance from the axis of rotation.
• The maximum will the value of V, if the r maximizes.
• Thus, child A with greater distance will have larger tangential speed.

Thus, we can conclude that, child A with greater distance will have larger tangential speed.

Learn more about the Angular velocity here:

brainly.com/question/28019892

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