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Svet_ta [14]
2 years ago
13

Two children are riding on a merry-go-round. Child A is at a greater distance from the axis of rotation than child B. Which chil

d has the larger tangential speed
Physics
1 answer:
Tamiku [17]2 years ago
7 0

Answer: Two children are riding on a marry-go-round. Child A is at a greater distance from the axis of rotation than child B. Thus, the child A, located at a greater distance from the axis of rotation have a larger tangential speed.

Explanation: To find the correct answer we have to know more about the Angular velocity of a rotating body.

<h3>What is the angular velocity?</h3>
  • In rotational motion, the angular velocity ω can be defined as, the change in angular displacement(Ф) per unit time (t).
  • It's the revolution per second.
  • The angular velocity can be expressed in terms of the tangential velocity as well as the radius of the circular path as,

                              w=V/r

<h3>How to solve the question?</h3>
  • We know that the expression for the tangential velocity as,

                               V=wr

  • In the question, for both the child, the value of w will be same. Thus, the only quantity that depends on the tangential velocity will be the distance from the axis of rotation.
  • The maximum will the value of V, if the r maximizes.
  • Thus, child A with greater distance will have larger tangential speed.

Thus, we can conclude that, child A with greater distance will have larger tangential speed.

Learn more about the Angular velocity here:

brainly.com/question/28019892

#SPJ4

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Water is leaking out of an inverted conical tank at a rate of 1.5 cm3 /min at the same time that water is being pumped into the
iris [78.8K]

Answer:

a) Check Explanation

b) Check Explanation

c) The rate at which water is being pumped into the tank = 2.631 cm³/min

Explanation:

Let the rate of flow of water into the tank be k cm³/min

a) The image of the conical tank is presented in the attached image

Note, the radius and height of a cone are related through the similar triangles principle.

As shown in the attached image, it is evident that

r/h = 3/10

r = 3h/10 = 0.3 h

b) The quantities given in the problem.

- Shape of the tank, conical tank, Hence volume of the tank = πr²h/3

- total height of the tank, H = 10 cm

- Radius of the tank at the top, R = D/2 = 6/2 = 3 cm

- rate at which water is leaking from the tank = 1.5 cm³/min

- water is being pumped into the tank at constant rate of k cm³/min

- As at height of water, h = 2 cm, the rate of rise in water level = 1 cm/min

c) volume of the tank at any time = πr²h/3

Rate of change in the volume of water in the tank = (rate of flow into the tank) - (Rate of water flow out of the tank)

dV/dt = k - 1.5

V = πr²h/3 and r = 0.3 h, r² = 0.09 h²

V = 0.03πh³

dV/dt = (dV/dh) × (dh/dt)

dV/dh = 0.09π h²

dV/dt = 0.09π h² (dh/dt)

dV/dt = k - 1.5

0.09π h² (dh/dt) = k - 1.5

But at h = 2 cm, (dh/dt) = 1.0 cm/min

0.09π h² (dh/dt) = k - 1.5

0.09π 2² (1) = k - 1.5

k - 1.5 = 1.131

k = 1.5 + 1.131 = 2.631 cm³/min

5 0
3 years ago
You have been training and can run a mile in 6.5 minutes. How long would it take to run a lap around the outside track, which is
Paha777 [63]

Answer:

1 minute 36.85 seconds

Explanation:

First we need to convert the miles into meters, as the demanded result should be in meters.

1 mile = 1,609.34 meters

Also, 6.5 minutes should be converted into seconds.

1 minute = 60 seconds

6.5 x 60 = 390 seconds

Now we need to divide the miles with the seconds to see how much meters have been run in a second.

1,609.34 / 390 = 4.13 meters

The suggested meters now should be divided with the distance run in one second.

400 / 4.13 = 96.85 seconds

So we get a result of 96.85 seconds, or 1 minute 36.85 seconds.

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between each, L = 0.85 m is the length of each rod.

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