Two children are riding on a merry-go-round. Child A is at a greater distance from the axis of rotation than child B. Which chil
1 answer:
Answer: Two children are riding on a marry-go-round. Child A is at a greater distance from the axis of rotation than child B. Thus, the child A, located at a greater distance from the axis of rotation have a larger tangential speed.
Explanation: To find the correct answer we have to know more about the Angular velocity of a rotating body.
<h3>What is the angular velocity?</h3>- In rotational motion, the angular velocity ω can be defined as, the change in angular displacement(Ф) per unit time (t).
- It's the revolution per second.
- The angular velocity can be expressed in terms of the tangential velocity as well as the radius of the circular path as,
- We know that the expression for the tangential velocity as,
- In the question, for both the child, the value of w will be same. Thus, the only quantity that depends on the tangential velocity will be the distance from the axis of rotation.
- The maximum will the value of V, if the r maximizes.
- Thus, child A with greater distance will have larger tangential speed.
Thus, we can conclude that, child A with greater distance will have larger tangential speed.
Learn more about the Angular velocity here:
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Answer:
The value of the distance is .
Explanation:
The velocity of a particle(v) executing SHM is
where, is the angular frequency,
is the amplitude of the oscillation and
is the displacement of the particle at any instant of time.
The velocity of the particle will be maximum when the particle will cross its equilibrium position, i.e., .
The maximum velocity() is
Divide equation (1) by equation(2).
Given, and
. Substitute these values in equation (3).