Two children are riding on a merry-go-round. Child A is at a greater distance from the axis of rotation than child B. Which chil
1 answer:
Answer: Two children are riding on a marry-go-round. Child A is at a greater distance from the axis of rotation than child B. Thus, the child A, located at a greater distance from the axis of rotation have a larger tangential speed.
Explanation: To find the correct answer we have to know more about the Angular velocity of a rotating body.
<h3>What is the angular velocity?</h3>- In rotational motion, the angular velocity ω can be defined as, the change in angular displacement(Ф) per unit time (t).
- It's the revolution per second.
- The angular velocity can be expressed in terms of the tangential velocity as well as the radius of the circular path as,
- We know that the expression for the tangential velocity as,
- In the question, for both the child, the value of w will be same. Thus, the only quantity that depends on the tangential velocity will be the distance from the axis of rotation.
- The maximum will the value of V, if the r maximizes.
- Thus, child A with greater distance will have larger tangential speed.
Thus, we can conclude that, child A with greater distance will have larger tangential speed.
Learn more about the Angular velocity here:
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The dimensions of the rectangle are:
l = 50 m
b = m
The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides.
<h3>How do we find a perimeter of a rectangle?</h3>The perimeter of a rectangle,denoted by P is given by the formula, P=2l+2b, where l is the length and b is the breadth of the rectangle.
<h3>Given:</h3>As per the question:
Perimeter of the room is given as P = 200 m
The region is rectangular having a semicircle at each end.
Now,
Let 'l' be the length of the rectangle, 'b' be its breadth and 'r' be the radius of the semi-circle at each end.
Then, Area of the given rectangle, A = lb
Perimeter of the room, P is =
Therefore,
Now,
Area, A =
Now, differentiate A w.r.t l:
Again differentiating w.r.t 'l', we get:
< 0
Thus we get maximum are when
Therefore,
l = 50 m
Now, from
To know more about area of a recatangle, visit the link
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