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Svet_ta [14]
1 year ago
13

Two children are riding on a merry-go-round. Child A is at a greater distance from the axis of rotation than child B. Which chil

d has the larger tangential speed
Physics
1 answer:
Tamiku [17]1 year ago
7 0

Answer: Two children are riding on a marry-go-round. Child A is at a greater distance from the axis of rotation than child B. Thus, the child A, located at a greater distance from the axis of rotation have a larger tangential speed.

Explanation: To find the correct answer we have to know more about the Angular velocity of a rotating body.

<h3>What is the angular velocity?</h3>
  • In rotational motion, the angular velocity ω can be defined as, the change in angular displacement(Ф) per unit time (t).
  • It's the revolution per second.
  • The angular velocity can be expressed in terms of the tangential velocity as well as the radius of the circular path as,

                              w=V/r

<h3>How to solve the question?</h3>
  • We know that the expression for the tangential velocity as,

                               V=wr

  • In the question, for both the child, the value of w will be same. Thus, the only quantity that depends on the tangential velocity will be the distance from the axis of rotation.
  • The maximum will the value of V, if the r maximizes.
  • Thus, child A with greater distance will have larger tangential speed.

Thus, we can conclude that, child A with greater distance will have larger tangential speed.

Learn more about the Angular velocity here:

brainly.com/question/28019892

#SPJ4

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Answer:

Explanation:

We shall represent displacement of dog in vector form , in terms of i , j , i representing east  and  j representing north .

Dog travels 3.5 m south .

Displacement D₁ = - 3.5 j

then dog travels 8.2 m , 23.1 degree north of east

Displacement D₂ = 8.2 cos23.1 i + 8.2 sin23 j

D₂ = 8.2 cos23.1 i + 8.2 sin23.1  j

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