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natka813 [3]
3 years ago
5

Is glycine a compound or a element

Chemistry
2 answers:
galben [10]3 years ago
8 0
Glycine is a coumpund. 
xxMikexx [17]3 years ago
7 0
Glycine is in fact a compound. :)
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If a student made a 2.5 solution using 1.5 moles of sucrose how many liters of water were used?
saul85 [17]

Answer:

1 mole.

Explanation:

Hello there!

2.5-1.5=1

Subtract the sucrose moles from the total moles, and there you are!

:)

3 0
3 years ago
When the procedure calls for making a more dilute solution of an acid, or mixing an acid with other solutions, what is the corre
stiks02 [169]

Explanation:

Whenever we need to make a dilute solution of an acid then it is necessary to add water or non-acidic component into the acid first. This is because addition of water or non-acidic component directly into the acid could be highly exothermic in nature.

As a result, the acid can splutter and can cause burning of skin and other serious damage.

So, in order to avoid such type of damage the addition of water or non-acidic component into the acid actually helps to minimize the heat generated.

Thus, we can conclude that correct order of steps for making a more dilute solution of an acid is that either add all of the water or non-acid component first, or add a significant portion, before adding the acid to the mixture.

8 0
3 years ago
Examine the images.
gavmur [86]

Answer:

4 th image

Explanation:

water is being boiled n the 4th image indicating that the change between liquids and gasses is water vapor.

5 0
3 years ago
Read 2 more answers
You operate a nuclear reactors and want to use fissionable mass that will sustain a slow control what type of mass will you use
puteri [66]

Answer: I believe it is critical mass

Explanation:

3 0
3 years ago
What is the empirical formula of a compound composed of 3.25% hydrogen ( H ), 19.36% carbon ( C ), and 77.39% oxygen ( O ) by ma
Montano1993 [528]

Answer:

The answer to your question is C₂HO₃

Explanation:

Data

Hydrogen = 3.25%

Carbon = 19.36%

Oxygen = 77.39%

Process

1.- Write the percent as grams

Hydrogen = 3.25 g

Carbon = 19.36 g

Oxygen = 77.39 g

2.- Convert the grams to moles

                     1 g of H ----------------- 1 mol

                   3,25 g of H -------------  x

                     x = (3.25 x 1) / 1

                     x = 3.25 moles

                    12 g of C ---------------- 1 mol

                     19.36 g of C ----------  x

                     x = (19.36 x 1) / 12

                     x = 1.61 moles

                     16g of O --------------- 1 mol

                     77.39 g of O ---------  x

                      x = (77.39 x 1)/16

                      x = 4.83

3.- Divide by the lowest number of moles

Carbon = 3.25/1.61 = 2

Hydrogen = 1.61/1.61 = 1

Oxygen = 4.83/1.61 = 3

4.- Write the empirical formula

                        C₂HO₃

4 0
3 years ago
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