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maksim [4K]
3 years ago
7

Pls helpits rlly hard

Chemistry
1 answer:
victus00 [196]3 years ago
5 0

Answer:

5: 0.16

6: 50

Explanation:

Question 5:

We can use the equation density = mass/ volume.

We already have the mass (12g), but now we need to find the volume of the cylinder.

The equation for this is πr²h

So we know the radius is 2 and the height is 6.

π x (2)² x 6 = 24π = 75.398cm³

Now we can use the density equation above:

12/75.398 = 0.1592g/cm³ = 0.16g/cm³.

Question 6:

This time, we have to rearrange the equation density = mass/ volume to find the mass.

We know mass = density x volume.

From the question, the density is 2.5g/mL and the volume is 20mL.

Following the equation above, we do 2.5 x 20 to get 50g.

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blondinia [14]
Step 1: Write Imbalance Equation

                            CH₃CHO  +  O₂    →    CO₂  +  H₂O

Step 2: Balance Carbon Atoms:
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                             CH₃CHO  +  O₂    →    2 CO₂  +  H₂O 

Step 3: Balance Hydrogen Atoms:
                                                      There are 4 hydrogen atoms at reactant side and 2 Hydrogen atoms at product side. So, multiply H₂O by 2 to balance Hydrogen on both sides. i.e.

                    CH₃CHO  +  O₂    →    2 CO₂  +  2 H₂O

Step 4: Balance Oxygen Atoms:
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                    CH₃CHO  +  5/2 O₂    →    2 CO₂  +  2 H₂O

Step 6: Eliminate Fraction:
                                         Multiply overall equation by 2 to eliminate fraction. i.e. 

                    2 CH₃CHO  +  5 O₂    →    4 CO₂  +  4 H₂O
7 0
3 years ago
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8 0
3 years ago
Considering the limiting reactant, what is the mass of zinc sulfide produced from 0.250 g of zinc and 0.750 g of sulfur? Zn(s)+S
DIA [1.3K]

Answer:

The mass of zinc sulfide produced is  M_{ZnS} =  0.76 \ g

Explanation:

From the question we are told that

   The mass of zinc is  m_z =  0.750 \ g

    The mass of sulfur is  m_s =  0.250 \ g

The molar mass   of  Zn_{(s)}  is a constant with value  65.39 g /mol

The molar mass of S_{(s)}  is a constant with value  32.01 g/mol

The molar mass of  ZnS_{(s)} is a constant with value 97.46  g/mol

The reaction is  

        Zn_{(s)} + S_{(s)}  ------> ZnS_{(s)}

   So from the reaction

       1 mole of  Zn_{(s)} react with 1 mole of  S_{(s)} to produce 1 mole of ZnS_{(s)}

This implies that

65.39 g /mol of  Zn_{(s)} react with 32.01 g/mol of  S_{(s)} to produce   97.46  g/mol  of ZnS_{(s)}

From the values given we can deduce that the limiting reactant is sulfur cause  of the smaller mass

 So  

    0.250 g of  Zn_{(s)} react with 0.250 of  S_{(s)} to produce x \  g of  ZnS_{(s)}

So

      x =  \frac{97.46 * 0.250}{32.01}

       x =  0.76 \ g

Thus the mass of the mass of zinc sulfide produced is

    M_{ZnS} =  0.76 \ g

 

     

7 0
4 years ago
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