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Zolol [24]
3 years ago
15

At standard pressure, the difference between the freezing point and the boiling point of water, in Kelvin degrees, is D. 373 A.

100 B. 180 C. 273
Chemistry
1 answer:
zepelin [54]3 years ago
6 0
Your answer would be A.100 
 
                                       

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Corrosion may be regarded as the destruction of metal by:
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2 years ago
What is the noble-gas configuration for As​
jasenka [17]

Answer:

Noble gas Electronic configuration of arsenic:

As₃₃ = [Ar] 3d¹⁰ 4s² 4p³

Explanation:

Arsenic is metalloid.

Its atomic number is 33.

Its atomic mass is 75 amu.

Its symbol is As.

It is usually present in combine with sulfur and metals.

it is used in bronzing.

It is also used for hardening.

Electronic configuration:

As₃₃ = Is² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p³

Noble gas Electronic configuration:

As₃₃ = [Ar] 3d¹⁰ 4s² 4p³

Noble gas electronic configuration is shortest electronic configuration by using the noble gas elements full octet electronic configuration.

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3 years ago
Aluminum reacts with a certain nonmetallic element to form a compound with the general formula AIX; where element X is a diatomi
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3 years ago
How do you think winds affect air pollution?
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3 years ago
400. mg of an unknown protein are dissolved in enough solvent to make 5.00 mL of solution. The osmotic pressure of this solution
ch4aika [34]

<u>Answer:</u> The molecular weight of protein is 1.14\times 10^2g/mol

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

or,

\pi=i\times \frac{m_{solute}\times 1000}{M_{solute}\times V_{solution}\text{ (in mL)}}}\times RT

where,

\pi = Osmotic pressure of the solution = 0.0861 atm

i = Van't hoff factor = 1 (for non-electrolytes)

m_{solute} = mass of protein = 400 mg = 0.4 g   (Conversion factor:  1 g = 1000 mg)

M_{solute} = molar mass of protein = ?

V_{solution} = Volume of solution = 5.00 mL

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[25+273]K=298K

Putting values in above equation, we get:

0.0861atm=1\times \frac{0.4g\times 1000}{M\times 100}\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 298K\\\\M=1136.62g/mol=1.14\times 10^2g/mol

Hence, the molecular weight of protein is 1.14\times 10^2g/mol

4 0
3 years ago
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