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2 years ago

Help!! plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz!!ASAP!!!

Physics

2 answers:

Firdavs [7]2 years ago

7 0

The answer would be C

alekssr [168]2 years ago

3 0

That is a closed switch

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An object is placed at 1.5 m from a convex lens with a focal length of 1.0 m.

AleksAgata [21]

A. Use the thin lens equation to determine the image distance from the lens. Is the correct answer because I have no idea why

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3 years ago

A student has designed a circuit with one battery, two light bulbs, and two switches, pictured to the left. She would like for e

Gnoma [55]

Answer:

The bulb is not powered because the negative end of the battery is not connected to the electric current,making it dysfunctional. The electrons have to flow through the positive and negative ends of the battery in order for it to work.

Hope this helps.

5 0

3 years ago

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Harry and ron set up this experiment with a glider, whose mass they have measured to be 565 g, and seven washers hanging from th

svetlana [45]

Let's call $m=565~g=0.565~kg$ the mass of the glider and $m_w=7\cdot12~g =84~g=0.084~kg$ the total mass of the seven washers hanging from the string.
The net force on the system is given by the weight of the hanging washers:
$F_{net} = m_w g$
For Newton's second law, this net force is equal to the product between the total mass of the system (which is $m+m_w$ ) and the acceleration a:
$F_{net}=(m+m_w)a$
So, if we equalize the two equations, we get
$m_w g = (m+m_w)a$
and from this we can find the acceleration:
$a= \frac{m_w g}{(m+m_w)} = \frac{0.084~kg \cdot 9.81~m/s^2}{(0.565~kg+0.084~kg)}=1.27~m/s^2$

5 0

3 years ago

Mitch throws a 100-g lump of clay at a 500-g target, which is at rest on a horizontal surface. After impact, the target, includi

max2010maxim [7]

Answer:

27.22 m/s

Explanation:

Let the speed of clay before impact is u.

the speed of clay and target is v after impact.

use conservation of momentum

momentum before impact momentum after impact

mass of clay x u = (mass of clay + mass of target) x v

100 x u = (100 + 500) x v

u = 6 v .....(1)

distance, s = 2.1 m

μ = 0.5

final velocity is zero. use third equation of motion

v'² = v² + 2as

0 = v² - 2 x μ x g x s

v² = 2 x 0.5 x 9.8 x 2.1 = 20.58

v = 4.54 m/s

so by equation (1)

u = 6 x 4.54 = 27.22 m/s

thus, the speed of clay before impact is 27.22 m/s.

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3 years ago

Select ALL that apply. The stages of a human's lifespan include:

Alex787 [66]

Answer:

The answers are A and C

Explanation:

the order of a humans lifespan is: Infancy, early childhood, adolescence, adulthood, then elderly

6 0

3 years ago

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