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elixir [45]
3 years ago
5

Help!! plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz!!ASAP!!!

Physics
2 answers:
Firdavs [7]3 years ago
7 0
The answer would be C
alekssr [168]3 years ago
3 0
That is a closed switch
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A stone is thrown with an initial speed of 11.5 m/s at an angle of 50.0 above the horizontal from the top of a 30.0-m-tall build
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Answer:

The magnitude of the horizontal displacement of the rock is 7.39 m/s.

Explanation:

Given that,

Initial speed = 11.5 m/s

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We need to calculate the horizontal displacement of the rock

Using formula of horizontal component

v_{x}=u\cos\theta

Put the value into the formula

v_{x}=11.5\times\cos50

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Hence, The magnitude of the horizontal displacement of the rock is 7.39 m/s.

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