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elixir [45]
3 years ago
5

Help!! plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz!!ASAP!!!

Physics
2 answers:
Firdavs [7]3 years ago
7 0
The answer would be C
alekssr [168]3 years ago
3 0
That is a closed switch
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Jose is loading his luggage into his car so that he can go to visit his grandmother. He lifts his suitcase up a 10 m staircase i
maxonik [38]

Answer:

The work done on the suitcase is, W = 600 J

Explanation:

Given,

The average force exerted by Jose on his suitcase,  F = 60 N

Jose carried the suitcase to a distance, S = 10 m

The work done on the suitcase is given by the relation

                           <em>W = F x S</em>

Substituting the given values in the above equation,

                            W = 60 N x 10 m

                                 = 600 J

Hence, the work done on the suitcase is, W = 600 J

3 0
3 years ago
Identify a situation in which you would want to have a high
Andreyy89

Answer: A voltmeter must have a high resistance where as an ammeter must have a low resistance.

Explanation:

A voltmeter is a device which is connected in parallel to the component across which voltage needs to be measured. In a parallel circuit voltage drop is same at the nodes. The parallel connection must not offer easier path for current to divert from the main circuit and travel. Thus, a voltmeter must have high resistance.

On the other hand, an ammeter which is used to measure current in the circuit must have low resistance as it is connected in series. It should not offer resistance as it would reduce the actual current and measurement would be inaccurate.

7 0
3 years ago
Read 2 more answers
What is the smallest part of a chemical compound that has all the properties
mel-nik [20]

Answer:

D. A Molecule

Explanation:

<em>The smallest particle of a compound that still has the properties of the compound is a molecule. It is composed of two or more bonded atoms.</em>

5 0
3 years ago
. Write the following in the scientific notation of 0.0000002400m ​
aleksandr82 [10.1K]

Explanation:

<h2><u>Steps </u><u>:</u></h2>
  1. <u>Move </u><u>decimal</u><u> </u><u>from</u><u> </u><u>left </u><u>to </u><u>right</u><u> </u><u>=</u><u>0</u><u> </u><u>0</u><u>0</u><u>0</u><u>0</u><u>0</u><u>0</u><u>2</u><u>4</u><u>0</u><u>.</u><u>0</u>
  2. <u>Then </u><u>count </u><u>the</u><u> </u><u>numbers</u><u> </u><u>before</u><u> </u><u>decimal </u><u>and </u><u>w</u><u>rite </u><u>it </u><u>like</u><u> </u><u>this </u><u>=</u><u>2</u><u>4</u><u>0</u><u>.</u><u>0</u><u>x</u><u>1</u><u>0</u><u> </u><u>power-</u><u>9</u><u> </u>
  3. <u>That's</u><u> </u><u>all </u>

<u>hope</u><u> it</u><u> </u><u>help</u>

<h2><u>#</u><u>H</u><u>o</u><u>p</u><u>e</u></h2>
7 0
2 years ago
A car moving with an initial speed v collides with a second stationary car that is one-half as massive. After the collision the
Mashutka [201]

Answer:

4v/3

Explanation:

Assume elastic collision by the law of momentum conservation:

m_1v = m_1v_1 + m_2v_2

where v is the original speed of car 1, v1 is the final speed of car 1 and v2 is final speed of car 2. m1 and m2 are masses of car 1 and car 2, respectively

Substitute m_2 = m_1/2 \& v_1 = v/3

m_1v = \frac{m_1v}{3} + \frac{m_1v_2}{2}

Divide both side by m_1, then multiply by 6 we have

6v = 2v + 3v_2

3v_2 = 4v

v_2 = \frac{4v}{3}

So the final speed of the second car is 4/3 of the first car original speed

5 0
3 years ago
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