We can find the maximum number of lines per centimeter, which is reciprocal of the least distance separating two adjacent slits, using the following equation.
mλ = dsin (θ)
In this equation,
m is the order of diffraction.
λ is the wavelength of the incident light.
d is the distance separating the centers of the two slits.
θ is the angle at which the mth order would diffract.
To find the least separation that allows the observation of one complete order of spectrum of the visible region, we use the maximum wavelength of the visible region is 700 nm.
d = mλ / sin (θ)
As we want the distance d to be the smallest then sin (θ) must be the greatest, and the greatest value of the sin (θ) is 1. For that we also use the longest wavelength because using the smallest wavelength, the longest wavelength would not be diffracted.
d = mλ / sin (θ)
d = 1 x 700nm / 1
= 700 nm
So, the least separation that would allow for the possibility of observing complete first order of the visible region spectra is 700 nm, and knowing the least separation we can find the maximum number of lines per cm, which is the reciprocal of the number of lines per cm.
n = 1/d
= 1 / 700 x
= 1, 430,000 lines per m
= 14,300 lines per cm
<u>The maximum number of lines per cm, that would allow for the observation of the complete first order visible spectra.</u>
<u>The following statements are false about collisions:
</u>
The velocity change of two respective objects involved in a collision will always be equal.
Total momentum is always conserved between any two objects involved in a collision.
Answer: Option B, and D
<u>Explanation:
</u>
In any collisions, equal amount of net force will be acted upon the colliding objects due to the third law of Newton, irrespective of the significance difference in mass of the objects. Similarly, they can also have different acceleration values during collision of two objects if the masses are identical.
But the statements regarding the equal change in velocity of two objects respectively involved in collision always is false, as the conservation of momentum is applicable for isolated system only. So it is true for only isolated system and not in all the systems.
The same reason goes for falsifying the fourth statement which states that total momentum is always conserved between two objects involved in a collision as this statement is only true for isolated system where the conservation of momentum can be applied. Thus the second and fourth statement is false regarding collision.
The galaxy is full of colors. There are various planets in the galaxy which are different colored. Their color is usually determined by the gases present there. The pink gases present near the Pluto makes Pluto appears to be of magenta or pink colored. The mercury is green colored because it reflects green rays. Mars is called the Red planet because of presence of Martin Rocks there.
Approximately of steam at (assuming that the boiling point of water in this experiment is .)
Explanation:
Latent heat of condensation/evaporation of water: .
Both mass values in this question are given in grams. Hence, convert the specific heat values from this question to .
Specific heat of water: .
Specific heat of copper: .
The temperature of this calorimeter and the of water that it initially contains increased from to . Calculate the amount of energy that would be absorbed:
.
.
Hence, it would take an extra of energy to increase the temperature of the calorimeter and the of water that it initially contains from to .
Assume that it would take grams of steam at ensure that the equilibrium temperature of the system is .
In other words, of steam at would need to release as it condenses (releases latent heat) and cools down to .
Latent heat of condensation from of steam: .
Energy released when that of water from the steam cools down from to :
.
These two parts of energy should add up to . That would be exactly what it would take to raise the temperature of the calorimeter and the water that it initially contains from to .
.
Solve for :
.
Hence, it would take approximately of steam at for the equilibrium temperature of the system to be .