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3 years ago

43.5 kg. Shawn rides his bike 1.3 km in

Physics

1 answer:

Alexeev081 [22]3 years ago

6 0

Answer:

K.E is 90.625 J

Explanation:

Data:

Mass = m = 43.5kg

Distance = d = 1.3km = 1300 m

Time = t = 10.4 min = 624 sec

Accelaration = a or g = 9.8

Formula for kinrtic energy

K.E = 1/2mv²

Find velocity

V = d/t = 1300/624 = 2.0833333333333 m/s

Put values in formula

K.E = 1/2 (43.5)(2.084)² = 90.624999999995

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An astronaut shipwrecked on a distant planet with unknown characteristics is on top of a cliff, which she wishes to descend. She

alexandr402 [8]

Answer:

y = 9.64 m

Explanation:

This exercise should be solved using kinematics in one dimension, let's write the equations for the two cases presented

The rock is released

y = y₀ + V₀₁ t₁ - ½ g t₁²

In this case the speed starts is zero

y = y₀ - ½ g t₁²

The rock is thrown up

y = y₀ + v₀² t₂ -½ g t₂²

The height that reaches the floor is zero

y₀ - ½ g t₁² = y₀ + v₀₂ t₂ - ½ g t₂²

We use the initial velocity with the equation

v₂² = v₀₂² - 2 g y

At the point of maximum height v₂ = 0

v₀₂ = √ (2 g $y_{max}$ )

g (-t₁² + t₂²) = 2 √ (2 g $y_{max}$ ) t₂²

g (- 4.15² + 6.30²) = 2 √ (2 2 g) 6.3

g (22.4675) = 25.2 √ g

g² = 2²5.2 / 22.4675 g

g = 1.12 m / s²

Having the value of g we can use any equation to find the height

y = ½ g t₁²

y = ½ 1.12 4.15²

y = 9.64 m

5 0

3 years ago

What graph would best represent acceleration as a function of mass when a constant force is applied?

Alex17521 [72]

The graphs of the acceleration as a function of mass and of the acceleration as a function of force are in attachment.

Explanation:

To answer both parts of the question, we refer to Newton's second law, which states that:

$F=ma$

where

F is the net force on an object

m is the mass of the object

a is its acceleration

To answer this part, we re-arrange the previous equation as follows:

$a=\frac{F}{m}$

Therefore, we notice that if a constant force is applied, the acceleration is inversely proportional to the mass of the object:

$a \propto \frac{1}{m}$

this means that if the mass increases, the acceleration decreases, and if the mass decreases, the acceleration increases.

In a graph of acceleration vs mass, the curve representing this relationship would be a hyperbole. The graph is shown as the first graph in the attached picture.

As before, we re-arrange the previous equation as follows:

$a=\frac{F}{m}$

Here we notice that if the object has a constant mass, the acceleration is directly proportional to the force applied on the object:

$a \propto F$

this means that when the force increases, the acceleration increases, and when the force decreases, the acceleration decreases.

In a graph of acceleration vs force, the curve representing this relationship would be a straight line, as shown in the second graph in the attached picture.

Learn more about Newton's second law of motion here:

brainly.com/question/3820012

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