Question

In the reaction C6H12 + ________ O2----> 6H20 + 6CO2, what coefficient should be placed in front of 02 to balance the reaction?

Answer 1

All you need to do is count the number of Oxygen the Products:
In 6H2O, you have 6 oxygen, and in 6CO2, you have 6 Dioxygen so 12 Oxygen. So a total of 12 + 6 = 18 atoms of Oxygen, or 9 atoms of dioxygen.
So the coefficient that should be placed in front of O2 to balance the reaction is 9:
C6H12 + 9O2 ---> 6H2O + 6CO2

Hope this Helps! :)

Answer 2

Answer : The coefficient placed in front of $O_2$ to balance the reaction should be, 9

Explanation :

Balanced chemical reaction : It is defined as the number of atoms of the individual elements present on reactant side in the reaction must be equal to the product side.

The given unbalanced chemical reaction is,

$C_6H_{12}+O_2\rightarrow 6H_2O+6CO_2$

This reaction is an unbalanced chemical reaction because in this reaction the number oxygen atoms are not balanced.

In order to balance the chemical reaction, we put the coefficient '9' before the oxygen molecule.

Thus, the balanced chemical reaction will be,

$C_6H_{12}+9O_2\rightarrow 6H_2O+6CO_2$

Hence, the coefficient placed in front of $O_2$ to balance the reaction should be, 9