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lana [24]
4 years ago
9

(a) what will an object weigh on the moon's surface if it weighs 100 n on earth's surface

Physics
1 answer:
juin [17]4 years ago
4 0
We know the equation

weight = mass × gravity

To work out the weight on the moon, we will need its mass, and the gravitational field strength of the moon.
Remember that your weight can change, but mass stays constant.

So using the information given about the earth weight, we can find the mass by substituting 100N for weight, and we know the gravity on earth is 10Nm*2 (Use the gravitational field strength provided by your school, I am assuming yours in 10Nm*2)

Therefore,

100N = mass × 10
mass= 100N/10
mass= 10 kg

Now, all we need are the moon's gravitational field strength and to apply this to the equation

weight = 10kg × (gravity on moon)
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A 900-kg car traveling east at 15.0 m/s collides with a 750-kg car traveling west at 20.0 m/s. The cars stick together. What is
andriy [413]

Answer:

17.27m/s

Explanation:

M1U1 + M2U2 = (M1+M2)V

(900x15) + (750 x 20) = (900+750)V

13500+15000 = (1650)V

28500 = 1650v

V = 28500/1650 = 17.27m/s

V = 17.27m/s

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3 years ago
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4 years ago
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You venture out on a cold winter morning to warm up your vehicle. You have layers of cotton/polyester blend clothes on and from
maxonik [38]

Answer:

A. There is a localization of positive charge near the door handle.

Explanation:

  • When on a cold morning a person wearing cotton/ polyester cloth walking on the carpet moves toward his car then due to friction between the feet and the carpet there are transfer of electrons from the carpet to our feet, and since our body is a good conductor of electricity the charges spread throughout on the surface of or body.
  • When the person brings his hands close to the neutral conducting door of the car it gets induced with equal intensity of opposite charge to our hands thus having a concentration of positive charges near to the hand on the car's door is developed as a result of polarization within the conductor.
3 0
3 years ago
Calculate the difference in blood pressure between the feet and top of the head for a person who is 1.70 m tall.
cupoosta [38]

Answer:

P_2 - P_1 = 1.8 * 10^4\ Pa

Explanation:

Given

Height (h) = 1.70m

Required

Determine the difference in the blood pressure from feet to top

This is calculated using Pascal's second law.

The second law is represented as:

P_2 = P_1 + pgd

Subtract P1 from both sides

P_2 - P_1 = pgd

Where

p = blood\ density = 1.06 * 10^3kg/m^3

g = acceleration\ of\ gravity = 9.8N/kg

d =height = 1.70m

P2 - P1 = Blood Pressure Difference

So, the expression becomes:

P_2 - P_1 = 1.06 * 10^3 * 9.8 * 1.70

P_2 - P_1 = 17659.6Pa

P_2 - P_1 = 1.8 * 10^4\ Pa

Hence, the difference in blood pressure is approximately 1.8 * 10^4\ Pa

3 0
3 years ago
A small sandbag is dropped from rest from a hovering hot-air balloon. (assume the positive direction is upward.) (a) after 1.5 s
marishachu [46]

solution:

We know v0 = 0, a = 9.8, t = 4.0. We need to solve for v

so,

we use the equation:

v = v0 + at

v = 0 + 9.8*4.0

v = 39.2 m/s

Now we just need to solve for d, so we use the equation:

d = v0t + 1/2*a*t^2

d = 0*4.0 + 1/2*9.8*4.0^2

d = 78.4 m

3 0
3 years ago
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