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butalik [34]
4 years ago
11

Which is one way to check 102÷6 = 17? A) 105÷10 = 10 .5 B) 17÷6 = 102 C) 100÷5 = 20 D) 100×5 = 500

Mathematics
1 answer:
Karolina [17]4 years ago
8 0
Was there a typo in the possible answers by any chance? B is closest to the possible answer, but only if the division sign was a multiplication sign.
102 <span>÷ 6 = 17
102 </span><span>÷ 17 = 6
17 x 6 = 102
6 x 17 = 102</span>
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Cheryl writes 7 fewer posts than Kevin on a social media site. Answer the questions to write an algebraic expression. Then evalu
Inessa [10]

Answer:

17

Step-by-step explanation:

8 0
3 years ago
A rectangle with a length of L and a width of W has a diagonal of 10 inches. Express the perimeter P of the rectangle as a funct
KatRina [158]
<h2>Answer:</h2>

The expression which represents the perimeter P of the rectangle as a function of L is:

          Perimeter=2(L+\sqrt{100-L^2})

<h2>Step-by-step explanation:</h2>

The length and width of a rectangle are denoted by L and W respectively.

Also the diagonal of a rectangle is: 10 inches.

We know that the diagonal of a rectangle in terms of L and W are given by:

10=\sqrt{L^2+W^2}

( Since, the diagonal of a rectangle act as a hypotenuse of the right angled triangle and we use the Pythagorean Theorem )

Hence, we have:

10^2=L^2+W^2\\\\i.e.\\\\W^2=100-L^2\\\\W=\pm \sqrt{100-L^2}

But we know that width can't be negative. It has to be greater than 0.

Hence, we have:

W=\sqrt{100-L^2}

Now, we know that the Perimeter of a rectangle is given by:

Perimeter=2(L+W)

Here we have:

Perimeter=2(L+\sqrt{100-L^2})

7 0
4 years ago
Which is the x coordinate of the point on the graph ?
dimaraw [331]

Answer:

-5

Step-by-step explanation:

Cuz it lines up to -5 on x-axis

4 0
3 years ago
Read 2 more answers
Help on question 2 please :/
irakobra [83]
40% is close to 50% which is = to 1/2
So just divide 60 by 2. which would be around 30

this is the best way i could explain, I hope this helps
8 0
3 years ago
Read 2 more answers
ABCD is a trapezium in which AB ∥ CD, AD ⊥ DC, AB = 4 cm, BP = 7 cm and DC = 25 cm, then area of the trapezium is 45.
Elza [17]

Question:

ABCD is a trapezium in which AB ∥ CD, AD ⊥ DC, AB = 4 cm, BP = 7 cm and DC = 25 cm, then area of the trapezium is ____.

Answer:

101.5cm²

Step-by-step explanation:

The figure for the trapezium ABCD is attached to this response.

To find the area of the trapezium, we use the formula for calculating the area of a trapezium given as follows;

A  = \frac{1}{2} x (a + b) x h            ------------------(i)

Where;

A = area of the trapezium

a and b are the parallel sides of the trapezium

h = height of the trapezium.

As shown in the figure,

<em>AB and CD are parallel</em>

Therefore, we can say that;

a = AB

b = CD

Also, from the figure,

<em>The height of the trapezium is BP</em>

Therefore, we can say that;

h = BP

We know that;

a = AB = 4cm

b = CD = 25cm

h = BP = 7cm

Substitute these values of a, b and h into equation (i) as follows;

A  = \frac{1}{2} x (4 + 25) x 7    

A  = \frac{1}{2} x (29) x 7    

A = 101.5

Therefore, the area of the trapezium is 101.5cm²

8 0
3 years ago
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