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expeople1 [14]
3 years ago
15

When fuel is burned in a cylinder equipped with a piston, the volume expands from 0.255 L to 1.45 L against an external pressure

of 1.02 atm. In addition, 875 J is emitted as heat. What is the DE for the burning of the fuel?
Chemistry
1 answer:
EastWind [94]3 years ago
8 0

Answer : The value of \Delta E for the burning of the fuel is, -998.5 joules.

Explanation :

First we have to calculate the work done.

Formula used :

w=-p_{ext}dV\\\\w=-p_{ext}(V_2-V_1)

where,

w = work done  = ?

p_{ext} = external pressure = 1.02 atm

V_1 = initial volume of gas = 0.255 L

V_2 = final volume of gas = 1.45 L

Now put all the given values in the above formula, we get :

w=-p_{ext}(V_2-V_1)

w=-(1.02atm)\times (1.45-0.255)L

w=-1.22L.atm=-1.22\times 101.3J=-123.5J

conversion used : (1 L.atm = 101.3 J)

Now we have to calculate the change in internal energy of the system.

\Delta E=q+w

\Delta E=-875J+(-123.5J)

\Delta E=-998.5J

Therefore, the value of \Delta E for the burning of the fuel is, -998.5 joules.

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