1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nikklg [1K]
3 years ago
7

Under which conditions of temperature and pressure would a 1-liter sample of a real gas behave most like an ideal gas?

Chemistry
2 answers:
VLD [36.1K]3 years ago
7 0

Answer:

The correct answer is (3).

Explanation:

A real gas can behave ideally at high temperatures and low pressures. The ideal gas is correctly characterized when the intermolecular interactions between the gas molecules and the volume of the gas molecule are negligible. This is only possible when system conditions are at low pressures and high temperatures.

Have a nice day!

Sladkaya [172]3 years ago
3 0

Answer : The correct option is (3) 500 K and 0.1 atm.

Explanation :

A real gas behaves ideally at high temperature and low pressure.

The ideal gas equation is,

PV=nRT

where,

P = pressure of gas

V = Volume of gas

R = Gas constant

T = temperature of gas

n = number of moles of gas

The ideal gas works properly when the inter-molecular interactions between the gas molecules and volume of gas molecule will be negligible. This is possible when pressure is low and temperature is high.

Therefore, the correct option is (3) 500 K and 0.1 atm.

You might be interested in
Beta particles will: 1. bend toward the North Pole of a magnet. 2 bend toward the South Pole of the magnet 3 not be affected by
Setler79 [48]
Beta particles will bend toward the South Pole of the magnet.

Hope this helped!
8 0
3 years ago
Read 2 more answers
At 850K, 65L of gas has a pressure of 450kPa. What is the volume (in liters) if the gas is cooled to 430K and the pressure decre
Novosadov [1.4K]

Answer:

V₂ =  45.53 L

Explanation:

Given data:

Initial temperature = 850 K

Initial volume = 65 L

Initial pressure = 450 KPa

Final temperature = 430 K

Final pressure = 325 KPa

Final volume = ?

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 450 KPa× 65 L × 430 K / 850 K × 325KPa  

V₂ = 12577500 KPa .L. K / 276250 K. KPa

V₂ =  45.53 L

8 0
3 years ago
In general, which of the following statements about electron-pair geometries is true?
Sergio [31]

Answer:

same

Explanation:

3 0
3 years ago
Explain how a motorcar engine produces nitrogen oxides
olya-2409 [2.1K]

Answer: combustion causes a chemical reaction between nitrogen and oxygen in the engine.

Explanation:

Nitrogen oxides are produced in combustion processes, partly from nitrogen compounds in the fuel, but mostly by direct combination of atmospheric oxygen and nitrogen in flames. Nitrogen oxides are produced naturally by lightning, and also, to a small extent, by microbial processes in soils.

4 0
3 years ago
Read 2 more answers
What is the balanced form of the following equation? Br 2 + S 2 O 3 2– + H 2 O → Br 1– + SO 4 2– + H +
nikitadnepr [17]

Answer:

4Br₂+ 5H₂O+ S₂O₃²⁻ → 2SO₄²⁻ + 10H⁺ + 8Br⁻

Explanation:

Br₂ +  S₂O₃²⁻  + H₂O  → Br⁻ + SO₄²⁻ + H⁺

This is a redox reaction:

Br₂ changes the oxidation state from 0 to -1, so it was reduced

In the S₂O₃⁻² anion S changes the oxidation state from +2 to +6 in sulfate anion. (S₂O₃⁻², it is called thiosulfate)

We have protons in the main equation, so we assume we are in acidic medium:

Br₂ + 2e⁻ → 2Br⁻         Reduction

We balanced the bromide with 2, so the bromine has gained 2 electrons.

<u>5H₂O</u> + S₂O₃²⁻ → 2SO₄²⁻ + <u>10H⁺</u> + <em>8e</em>-  Oxidation

First of all, we add 2 to the sulfate anion in the product side, in order to balance the S.

As we have 8 O in right side, and 3 O in left side, we must add 5 O. We add 5 water in the place where the O are lower (reactant side).

Now, we have 10 H, in the reactant side, so we balance the product side with protons (10 H⁺).

Sulfur changed the oxidation state from +2 to +6, so it released 4 electrons, but, if you see thiosulfate anion you have 2 sulfurs so finally it has released 8 electrons.

Electrons are unbalanced so we multiply reduction x4, and oxidation x1.

(Br₂ + 2e⁻ → 2Br⁻) . 4 = 4Br₂ + 8e⁻ → 8Br⁻

(5H₂O + S₂O₃²⁻ → 2SO₄²⁻ + 10H⁺ + <em>8e</em>-) . 1 = STAYS THE SAME.

We sum both half reactions, to cancel the elecetrons:

4Br₂ + 8e⁻ + 5H₂O + S₂O₃²⁻  → 2SO₄²⁻ + 10H⁺ + <em>8e</em>- + 8Br⁻

Finally the balanced reaction is: 4Br₂+ 5H₂O+ S₂O₃²⁻ → 2SO₄²⁻ + 10H⁺ + 8Br⁻

5 0
3 years ago
Other questions:
  • Balance each equation by entering the correct coefficients.
    8·1 answer
  • What kind of mixture is a solution? A suspension? A colloid?
    5·1 answer
  • Insoluble sulfide compounds are generally black in color.
    5·1 answer
  • Three of the primary components of air are
    12·1 answer
  • What statement is true about isotopes?
    11·1 answer
  • Why are groups 1 and 2 referred to as the s-block of the periodic table
    12·1 answer
  • Ok so brainly deleted My two accounts I had to make a new one because they deleted my first one and then after I made that new o
    8·1 answer
  • Silver has a density of 10.5 grams/cm3. What would be the mass of a 5 cm3 piece of sliver
    8·1 answer
  • Mixing baking soda and vinegar is an example of an endothermic reaction. This means...
    12·2 answers
  • If the pH of a solution is 8.45, what is the concentration of the OH-?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!