Answer: 83.11 torr
Explanation:
According to Dalton's Law of partial pressure, the total pressure of a mixture of gases is the sum of the pressure of each individual gas.
i.e Ptotal = P1 + P2 + P3 + .......
In this case,
Ptotal = 384 torr
P1 = 289 torr
P2 = 11.89 torr
P3 = ? (let the partial pressure of the remaining gas be Z)
Ptotal = P1 + P2 + Z
384 torr = 289 torr + 11.89 torr + Z
384 torr = 300.89 torr + Z
Z = 384 torr - 300.89 torr
Z = 83.11 torr
Thus, the partial pressure of the remaining gas is 83.11 torr.
0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.
<h3>HOW TO CALCULATE NUMBER OF MOLES?</h3>
The number of moles of a substance can be calculated using the following expression:
PV = nRT
Where;
- p = pressure (atm)
- v = volume (L)
- n = number of moles
- R = gas law constant
- T = temperature
0.75 × 11.2 = n × 0.0821 × 300
8.4 = 24.63n
n = 8.4 ÷ 24.63
n = 0.34 moles
Therefore, 0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.
Learn more about number of moles at: brainly.com/question/1190311
Answer:
All are correct
Explanation:
This might be a little deceptive. The question shows H, O and N which would designate ELEMENTS.
However, all of these can also be considered compounds and molecules as well. BUT, they are H₂, O₂ and N₂ when they are molecules and compounds.
So it depends on the whether the question is being literal or not.
