Explanation
Given that Sn = Sn-2 . (Sn-1 - 1)
Tn = Sn - Sn-1
Tn = Sn-2 . (Sn-1 - 1) - (Sn-3 . (Sn-2 - 1))
T3 = S1.(S2-1) - (S0.(S1-1)
T3 = 2.(3-1) - 1.(2-1)
T3 = 2(2) - 1(1)
T3 = 4-2
T3 = 3
T4 = S2.(S3-1) - (S1.(S2-1)
T4 =3.(-1) - 1.(2-1)
T4 = 2(2) - 1(1)
T4 = 4-2
T4 = 3
I think it’s the second option
L.H.S is already equal, so just subtract 1st equation from second,
2y = 12
y = 6
Now, substitute it in 1st equation,
2(6) = 4x + 8
4x = 12 - 8
x = 4/4
x = 1
In short, Your Answer would be Option C) (1, 6)
Hope this helps!
False.
y= 3(1)+1= 4
y= 3(2)+1=7 not 5
y= 3(3)+1=10 not 6
