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Stella [2.4K]
3 years ago
14

A motorcycle travels 889 meters in 15 seconds. What is its average speed?______m/s

Physics
2 answers:
Butoxors [25]3 years ago
8 0
So here you would have to do 
distance = time x speed.
distance is 889 meters
time is 15 seconds.
so 889 = 15 x speed
divide 15 on both sides.
889/15
Average speed is 59.2666667 m/s 
if it says in the question to round it then just round it. 
But whilst checking to see if this answer is correct, i did 59.2666667 multiplied by 15, which equals 889
hope this helped.

german3 years ago
6 0
The answer is about 59.3 m/s
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Answer:

The average number of calories needed daily represents the average quantity of calories eliminated by human body due to metabolism and must be compensated by eating and drinking.

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Explanation:

The average number of calories needed daily represents the average quantity of calories eliminated by human body due to metabolism and must be compensated by eating and drinking. If total quantity of calories in the food we consume every day is higher that the average number of calories needed daily, then weight increases by fat accumulation.

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an object with a mass of 2.4 kg has a force of 12.6 N applied to it. What is the resulting acceleration of the object? WITH PROO
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Starting from Newton’s law of universal gravitation, show how to find the speed of the moon in its orbit from the earth-moon dis
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Explanation:

According to Newton's law of universal gravitation:

F=G\frac{Mm}{r^{2}} (1)

Where:

F is the gravitational force between Earth and Moon

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M=5.972(10)^{24} kg is the mass of the Earth

m=7.349(10)^{22} kg is the mass of the Moon

r=3.9(10)^{8} m is the distance between the Earth and Moon

Asuming the orbit of the Moon around the Earth is a circular orbit, the Earth exerts a centripetal force on the moon, which is equal to F:

F=m.a_{C} (2)

Where a_{C} is the centripetal acceleration given by:

a_{C}=\frac{V^{2}}{r} (3)  

Being V the orbital velocity of the moon

Making (1)=(2):

m.a_{C}=G\frac{Mm}{r^{2}} (4)

Simplifying:

a_{C}=G\frac{M}{r^{2}} (5)

Making (5)=(3):

\frac{V^{2}}{r}=G\frac{M}{r^{2}} (6)  

Finding V:

V=\sqrt{\frac{GM}{r}} (7)

V=\sqrt{\frac{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.972(10)^{24} kg)}{3.9(10)^{8} m}} (8)

Finally:

V=1010.92 m/s

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